Implement the circuit (draw the schematic) using thedifferent implementation methods for the 4 logicfunctions b3M2, b2M2, b1M2 et b0M2:b2M2: With a 16 to 1 multiplexerb1M2: With an 8 to 1 multiplexer.bOM2: With a decoder and an OR logic gate.OOOO0DDOD0D11111111OOOOHHHD1110DD01111OOHHOHHOCHHOOHH00101101CHOHO001D10CHOHOHOHO.1011101b3 M20ONOC100OOOHPCHAT0001d01dd11d62 M20HOHOCal000FREETROOTd1dd00db1 M20HOL00101d10PPOddHOD0db0 M201011010d00dd01d

The truth table is given as Here , we need to design ⇒b2 by using 16×1 MUX.⇒b1 by using 8×1 MUX.⇒b0…

Implement the circuit (draw the schematic) using the different implementation methods for the 4 logic functions b3M2, b2M2, b1M2 et bOM2: b2M2: With a 16 to 1 multiplexer b1M2: With an 8 to 1 multiplexer. bOM2: With a decoder and an OR logic gate.

Implement the circuit (draw the schematic) using the different implementation methods for the 4 logic functions b3M2, b2M2, b1M2 et bOM2: b2M2: With a 16 to 1 multiplexer b1M2: With an 8 to 1 multiplexer. bOM2: With a decoder and an OR logic gate.

Electric Motor Control

10th Edition

ISBN:9781133702818

Author:Herman

Publisher:Herman

Chapter22: Sequence Control

Section: Chapter Questions

Problem 6SQ: Draw a symbol for a solid-state logic element AND.

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Question

Implement the circuit (draw the schematic) using the
different implementation methods for the 4 logic
functions b3M2, b2M2, b1M2 et b0M2:
b2M2: With a 16 to 1 multiplexer
b1M2: With an 8 to 1 multiplexer.
bOM2: With a decoder and an OR logic gate.
OOOO
0
D
D
OD
0
D
1
1
1
1
1
1
1
1
OOOOHHH
D
1
1
1
0
D
D
0
1
1
1
1
OOHHOHHOCHHOOHH
0
0
1
0
1
1
0
1
CHOHO
0
0
1
D
1
0
CHOHOHOHO.
1
0
1
1
1
0
1
b3 M2
0
ONOC
1
0
0
OOOHPCHAT
0
0
0
1
d
0
1
d
d
1
1
d
62 M2
0
HOHOC
al
0
0
0
FREETROOT
d
1
d
d
0
0
d
b1 M2
0
HOL
0
0
1
0
1
d
1
0
PPO
d
d
HOD
0
d
b0 M2
0
1
0
1
1
0
1
0
d
0
0
d
d
0
1
d

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