The solid cylinders AB and BC are bonded together at B and are attached to fixed supports at A and C. The modulus of rigidity is 3.1 106 psi for aluminum and 5.2 x 106 psi for brass. If T = 16 kip-in, a-1.1 in. and b-2.2 in., determine (a) The reaction torque at A (b) Maximum shear stress in BC Aluminum- Beam 12 m Assuming the reaction torque at A is TA (kip.in)(4). TA<16(kip.in) express the magnitude of (1) the internal reaction torque from A to B as TAB ( (i) the internal reaction torque from B to C as Tec TA+ TA+ ) (kip.in) ) (kip.in)

The steel frame shown below (E = 29,000 ksi) is subjected to a single lateral force of 20 kips. The supports at D, E, and F can be assumed fully fixed, and the joints at A, B, and C are rigid. Conduct a moment distribution on the frame to determine the magnitude of the fixed-end moments at support E (in units of k-ft). Note: The moment of inertia of column CF is also 400 in“. A |= 600 in В | = 600 in C 20 kips 20 ft | = 400 in4 | = 400 in4 D E F 40 ft 40 ft

1: A stepped shaft ACB having a solid circular cross sections with two different diameters and two different materials joined and attached at their ends, in the fisrt section AC of aluminum has a diameter of 20mm lenght of 225mm and G= 28x109 N/m2 and in the second section CB of steel has a diameter of 25mm leght 450mm and G=83x109N/m2. The torque appied is of 1000N.m and applied in the joint of the pieces. Determine the shear stress in both the aluminium and the steel.