The beam is supported by a pin at C and by a short link AB. Each pin has a diameter of 18 mm. Assume L = 1.6 m and 9 = 20°. If th average shear stress in the pins at A, B, and C cannot exceed 115 MPa, determine the maximum distributed load Wmax that can b supported by the structure. A (1) 0 1

Fill in the Blank Question: Simulations that have time derivative terms in their governing equations are considered to be _________ in nature?

Q.2 The following data relates to the office air conditioning plant having maximum seating capacity of 25 occupants : Recirculated air Room Outside air 4) to = 34°C tm = 28°C ta2 = 24°C $2 = 50% Mixing Coil Outside design conditions: 34°C DBT, 28°C WBT Inside design conditions: 24°C DBT, 50% RH Solar heat gain= 9120 W Latent heat gain per occupant= 105w Sensible heat gain per occupant=90w Lightening load= 2300 W Sensible heat load from other sources= 11630 W Infiltration load= 14 m³/min Assuming 40% fresh air and 60% of recirculated air passing through the evaporator coil and the by-pass factor of 0.15. Draw the process on psychrometric chart and find the dew point temperature of the coil and capacity of the plant.

1. A motor coil can be modeled as a hollow copper cylinder with an outer diameter of 0 50 mm, an inner diameter of 40 mm, and a length of 60 mm. The motor stalls at time t = 0 and, at this point, the copper experiences a step input in electrical heating of Po u(t), where Po is 350 W. Assume that there is little time for significant heat loss to the environment so that the copper cylinder can be considered to be insulated. If the initial temperature is 30 °C, find the temperature as a function of time, T(t), analytically using Laplace transforms. Calculate the time required to reach the breakdown temperature of the wire insulation, which is approximately 250 °C. Write a script file in MATLAB® to: (a) determine the time for the copper to reach 250 °C using the command find; and (b) plot T(t) over this time interval. Copper has a density of 8960 kg/m³ and a specific heat of 390 J/kg-°C. 25 mm 20 mm P(t) = Pou(t)