The steel frame shown below (E = 29,000 ksi) is subjected to a single lateral force of 20 kips. The supports at D, E, and F can be assumed fully fixed, and the joints at A, B, and C are rigid. Conduct a moment distribution on the frame to determine the magnitude of the fixed-end moments at support E (in units of k-ft). Note: The moment of inertia of column CF is also 400 in“. A | = 600 in* В | = 600 in* 20 kips 20 ft |= 400 inª | = 400 in4 D E F 40 ft 40 ft

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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The steel frame shown below (E = 29,000 ksi) is subjected to a single lateral
force of 20 kips. The supports at D, E, and F can be assumed fully fixed, and
the joints at A, B, and C are rigid. Conduct a moment distribution on the
frame to determine the magnitude of the fixed-end moments at support E
(in units of k-ft). Note: The moment of inertia of column CF is also 400 in“.
A
|= 600 in
В
| = 600 in
C
20 kips
20 ft
| = 400 in4
| = 400 in4
D
E
F
40 ft
40 ft
Transcribed Image Text:The steel frame shown below (E = 29,000 ksi) is subjected to a single lateral force of 20 kips. The supports at D, E, and F can be assumed fully fixed, and the joints at A, B, and C are rigid. Conduct a moment distribution on the frame to determine the magnitude of the fixed-end moments at support E (in units of k-ft). Note: The moment of inertia of column CF is also 400 in“. A |= 600 in В | = 600 in C 20 kips 20 ft | = 400 in4 | = 400 in4 D E F 40 ft 40 ft
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