The shaded region in the diagram below is a region of uniform electric field that is parallel to the horizontal direction (x-axis). A charge =4.3 uC moves through this region as shown by the green arrow. (a) If the charge accelerates as it moves from A to B, what is the direction of the electric field in this region? O to the left O to the right (b) The work done by the electric field as the charge moves from location A to location B is +2.50 x 10 J. What is the potential difference V- V?

Consider the diagram showing a positive charge in a uniform field. In order for an external force to do zero work on the charge the charge should be moved due east in the field. V upper E Vlower True False N E

Item 15 When a nerve impulse propagates along a nerve cell, the electric field within the cell membrane changes from 7.0×105 N/C in one direction to 3.1×105 N/C in the other direction. Part A Approximating the cell membrane as a parallel-plate capacitor, find the magnitude of the change in charge density on the walls on the cell membrane. Express your answer using two significant figures. ΠΙΑΣΦΑ |Aσ| = Submit Request Answer ? C/m²

A uniform electric field of magnitude 315 V/m is directed in the negative y direction as shown in the figure below. The coordinates of point  are (−0.400, −0.750) m, and those of point  are (0.450, 0.300) m. Calculate the electric potential difference VB − VA using the dashed-line path.

In image a) below 12 electrons are placed on the sides of a circle of radius R at the same distance, while in image b) the twelve electrons are placed on the sides of a circle covering 120° A. Calculate the electric potential at point C (center of the circle) for images a) and b) B. Draw the electric field at point C for images a) and b)

Consider the equipotential map shown below. Estimate the magnitude of the E-field at point A. What direction is the E-field at point A? Rank the points A, B, and C in terms of their E-field strength. Sketch the electric field lines. What is the sign of the charge (+ or −) within the 30 V equipotential?

When a charged particle is released from rest, at any point between two parallel plates, as shown in the following figure: E It is correct to state that: a) If the particle is an electron it will move in the direction from A to B and its electric potential energy increases. b) If the particle is an electron it will move in the direction from B towards A and its electric potential energy does not change. c) If the particle is a proton it will move in the direction from B toward A and its electric potential energy increases. d) If the particle is a proton it will move in the direction from A to B and its electric potential energy decreases.

In the pictured region of space, the electric field is equal to 200 N/C (oriented in the y-axis direction).  The spacing between the grid lines is 1.0 cm.  The goal of the problem is to calculate the potential difference between points A and B, by doing a path integral by hand. I need help with parts A-D

A point charge q = +39.0 µC moves from A to B separated by a distance d = 0.195 m in the presence of an external electric field  of magnitude 290 N/C directed toward the right as in the following figure. (a) Find the electric force exerted on the charge. magnitude      _______ N direction     toward the right toward the left The magnitude is zero. (b) Find the work done by the electric force. ______ J(c) Find the change in the electric potential energy of the charge. ______ J(d) Find the potential difference between A and B.VB − VA =  _______ V

Determine the electric field intensity and 's) the electric potential at a point P(0, 0, z) for z> 0, due to a rectangular disk of uniform surface charge density Ps = Po[C/m²] as shown in the figure. y=-a x=-b Ꮓ P(0,0,z) y=a x=b Ps = Po[C/m²] x y