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The amount of work you have to do to move a charge q from point P1 to point P2 through a small
displacement Ar in the presence of an electric field E is given by:
O is the angle between the direction
AW=F
· Ar = - qE·Ar =- q |E| |Ar| cosq.
of the electric field and the direction
you exert
of displacement Ar.
This tells us that the work is dependent on: the magnitude and type (+ or -) of the electric charge we
are trying to move, the strength of the electric field we are moving it through, the displacement
(change in position from starting point to ending point), and the angle the displacement makes with
the electric field.
1) If the angle the displacement makes with the electric field is 90° it means the charge is moving
across (or perpendicular to) the field vectors. Is work being done and what is doing the work?
Will it be Maximum, Minimum or zero? Explain your answer with a diagram.
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Transcribed Image Text:The amount of work you have to do to move a charge q from point P1 to point P2 through a small displacement Ar in the presence of an electric field E is given by: O is the angle between the direction AW=F · Ar = - qE·Ar =- q |E| |Ar| cosq. of the electric field and the direction you exert of displacement Ar. This tells us that the work is dependent on: the magnitude and type (+ or -) of the electric charge we are trying to move, the strength of the electric field we are moving it through, the displacement (change in position from starting point to ending point), and the angle the displacement makes with the electric field. 1) If the angle the displacement makes with the electric field is 90° it means the charge is moving across (or perpendicular to) the field vectors. Is work being done and what is doing the work? Will it be Maximum, Minimum or zero? Explain your answer with a diagram.
Expert Solution
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Step 1

Work done on the charge is given by the expressionW=-qErcosφφ is the angle between the displacement vector r and electric field E

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