The sample large power system network data's are given below, The total number of buses is 5 Three-phase short circuit fault subjected at the bus 5 The initial voltage of the faulted bus is 1.0 p.u The Zbus matrix element Z55 is 0.804 p.u Fault impedance Z;= 0.46 p.u Fault current (If )in p.u

The sample large power system network data's are given below, The total number of buses is 5 Three-phase short circuit fault subjected at the bus 5 The initial voltage of the faulted bus is 1.0 p.u The Zbus matrix element Z55 is 0.804 p.u Fault impedance Z;= 0.46 p.u Fault current (If )in p.u

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter8: Symmetrical Components

Section: Chapter Questions

Problem 8.36P

See similar textbooks

Related questions

Q: If a generator double-line-to-line fault occurs across "b" and "c" to ground, and Ea = 235 VZ0°, Z,…

A: In this question we need to find a sequence current , fault current and sequence voltage.

Q: the per unit bus impedance matrix for the power system shown in the Figure.FIND THE ZBUS

Q: Formulate the ???? matrix for the network shown here. 2. Modify ???? in the previous problem if the…

A: Redraw the circuit Given values : Y1-3 = j0.30Y1-2 = j0.24Y2-3 = j0.16 Z1-2 = j0.20Z2-3 =…

Q: Problem:1 The following is the system data for a load flow solution. Determine the bus voltages at…

Q: Consider the one-line diagram of power system shown below; a) Develop equivalent circuit expressing…

Q: Consider a 220-kV transmission system shown in Figure Q2. The per phase the impedances of the lines…

A: Given V=220 kV Z01=2+j 20 Ω Z02 =2.5 +j 25 Ω P=100 MVA

Q: A three-phase fault with a fault impedance Zf = j0.16 per unit occurs at bus 3 in the Figure beside,…

A: The answer is 2. Please fill answer only 2.

Q: For the four bus system as shown in Fig. Determine the fault current when the fault takes place at…

A: In this question, we will find fault impedance and current ..

Q: B) Develop an expression, in terms of the generated e.m.f. and the sequence impedances (ZI, Z2 and…

A: Solution (B) - For phase A, the line to earth fault is shown below,

Q: Above is the one-line diagram of a simple power system. Each generator is represented by an emf…

A: The Given symmetric fault occurs 1 through a fault impedance Zi=j0.08 perunit. To determine the…

Q: Obtain the bus admittance matrix for the given 5-bus power system.

A: Explanation:

Q: Consider a system operating at rated values with sequence impedances given by Z, = j0.2577, Z,=…

A: A single line-to-ground failure happens when one conductor meets the neutral conductor or falls to…

Q: In fault analysis the resistance of the power system network components is neglected and the…

A: Given In fault condition we neglect resistances True or false

Q: Problem 7. Three-phase Balanced Fault Analysis. For the two-generator system below, a three-phase…

Q: Problem2 A generator having H = 6.0 MJ /MVA is delivering power of 1 per unit to an infinite bus…

Q: A generating plant containing three identical 40 MW generating units is connected to a constant 82…

A: SI No Unit Failure rate Repair time Frequency Duration Failure probability 1 40 MW 3…

Q: At the end of the 8 km overhead line given in the figure below, there are two distribution…

A: According to question: The currents 'I1' and 'I2' in the distribution transformer is calculated as

Q: The sample large power system network data's are given below, The total number of buses is 5…

A: There are two types of symmetrical faults: a) Three-phase short circuit fault. b) Three-phase to…

Q: The figure attached to this question shows the 1 line diagram of a simple three bus power system…

A: Convert the line impedances into admittances, using Y=1/Z

Q: Q. No. 1. Figure I shows the single-line diagram of a simple four-bus system. Table 1 gives the line…

A: "Since you have asked a question with multiple subparts, I will answer only first three subparts of…

Q: For the four bus system as shown in Fig. Determine the fault current when the fault takes place at…

Q: The sample large power system network data's are given below, The total number of buses is 5…

A: Given data The total number of buses are 5 Three-phase short circuit fault subjected at the bus 5…

Q: The sample large power system network data's are given below, The total number of buses is 5…

Q: load flow for the 3 bus system shown in the figure. You should assume that bus 3 is the slack bus…

A: We are authorized to answer three one question at a time, since you have not mentioned which part…

Q: For the four bus system as shown in Fig. Determine the fault current when the fault takes place at…

A: Zth is the the impedance seen from Fault point. Fault current=Pre fault currentZth.

Q: For the four bus system as shown in Fig. Determine the fault current when the fault takes place at…

A: In this question , we have to find out fault current through fault point when fault occur at bus…

Q: Problem:1 The following is the system data for a load flow solution. Determine the bus voltages at…

A: Given data: α=1.6

Q: A three-phase fault with a fault impedance Zf = jo.16 per unit occurs at bus 3 in the Figure beside,…

A: The solution is given below

Q: B) Develop an expression, in terms of the generated e.m.f. and the sequence impedances (ZI, Z2 and…

A: According to the question we have, Develop an expression, in terms of the generated e.m.f. and the…

Q: A 345-kV transmission line has a series impedance of (4 + j60) Q and a shunt admittance of j2 ×…

A: Given values are - SBase=100MVAVBase=345kVZ=4+j60Y=j2×10-3S

Q: Draw the reactance diagram of the system whose single line diagram is given below and load flow in…

A: For the given system we need to find a bus admittance matrix and reactance diagram of a given…

Q: Q1. A// Choose the correct answer: 1. One of the advantage of using a per unit system in power…

A: According to guidelines we are allowed to do only first 3 questions , please post again for…

Q: For the four bus system as shown in Fig. Determine the fault current when the fault takes place at…

A: In this question , we will find thevenin impedance across fault point and fault current in pu..

Q: Find the short circuit current at the D point with the bus-admittance method of the system, whose…

A: Converting DELTA (BCD) into STAR

Q: The sample large power system network data's are given below, The total number of buses is 5…

A: In this question we have to find fault current...From z bus matrix..

Q: Thevenin equivalents of the zero, positive, and negative sequence circuits, respectively, seen from…

A: Each question has multiple subparts to solve. We are authorized to answer three subparts at a time,…

Q: Explain load flow analysis of radial distribution system using fuzzy logic with neat diagram

Q: The sample large power system network data's are given below, The total number of buses is 5…

A: In this question , we will find fault current with z bus matrix..

Q: For the four bus system as shown in Fig. Determine the fault current when the fault takes place at…

A: In the power system, Determine the fault current if the fault occurred at bus 2. Positive sequence…

Q: The per unit impedance of s circuit element of 0.15. If the base kV and base MVA are halved, then…

A: Given, The per unit impedance of a circuit element of 0.15, Zpuold=0.15 Base kV is halved,…

Q: For the power system shown at right the impedance matrix 2 is j0.5 j0.2 3 j0.4 0.145 0.120 0.0692…

A: New voltage at a bus = old bus voltage + change in voltage

Q: The figure below shows the one-line diagram of a four- bus power system. The voltages, the scheduled…

A: Note: We are authorized to answer three subparts at a time since you have not mentioned which part…

Q: Q1. All Choose the correct answer: 1. One of the advantage of using a per unit system in power…

A: As per the guidelines of Bartley we supposed to answer first three subpart only.

Q: Choose the right answer. 1. The symmetrical component method is …………. 2. Conditions for succesful…

A: 1) Symmetrical component method:- This method is used to solve the set of coupled equations. In this…

Q: Most buses in a typical power-flow program are a.voltage controlled bus b.PQ bus c.PV bus…

A: We are authorized to answer one question at a time, since you have not mentioned which question you…

Q: (b) Figure Q2(b) represents a single-line diagram of typical power system with the line impedances…

Q: (1) In terms of load assessment, define the following: Demand Factor Load Factor Diversity

A: As per the guidelines of Bartley we supposed to answer first question only since both question are…

Q: estion Shunt capacitors are used for lagging power factor circuits created by the heavy loads on…

Concept explainers

Compensation Techniques

The compensation techniques are the methods that are employed in the electrical control systems to enhance the performance of the system. The performance are generally affected by the factors like lag in the compensating devices, slow response of the system of the components like sensors used in the control system. The basic compensation technique involves lag compensation, lead compensation or the combination of the both.

Question

The sample large power system network data's are given below,
The total number of buses is 5
Three-phase short circuit fault subjected at the bus 5
The initial voltage of the faulted bus is 1.0 p.u
The Zbus matrix element Z55 is 0.804 p.u
Fault impedance Z;= 0.46 p.u
Fault current (If)in p.u

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Compensation Techniques in Transmission Line

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.

Similar questions

Equipment ratings for the five-bus power system shown in Figure 7.15 are as follows: Generator G1:Â Â Â Â 50Â MVA,Â 12kV,Â X=0.2 per unit Generator G2: 100Â MVA, 15 kV, X=0.2 per unit Transformer T1: 50 MVA, 10 kV Y/138kVY,X=0.10 per unit Transformer T2: 100 MVA, 15 kV /138kVY,X=0.10 per unit Each 138-kV line: X1=40 A three-phase short circuit occurs at bus 5, where the prefault voltage is 15 kV. Prefault load current is neglected. (a) Draw the positive-sequence reactance diagram in unit on a 100-MVA, 15-kV base in the zone of generator G2. Determine (b) the ThĂ©venin equivalent at the fault, (c) the subtransient fault current in per unit and in kA rms, and (d) contributions to the fault from generator G2 and from transformer T2.
The sample large power system network data's are given below, The total number of buses is 5 Three-phase short circuit fault subjected at the bus 5 The initial voltage of the faulted bus is 1.0 p.u The Zbus matrix element Z55 is 0.704 p.u Fault impedance Zf= 0.33 p.u Fault current (If )in p.u ..........
The sample large power system network data's are given below, The total number of buses is 5 Three-phase short circuit fault subjected at the bus 5 The initial voltage of the faulted bus is 1.0 p.u The Z matrix element Z55 is 0.474 p.u Fault impedance Z= 0.46 p.u Fault current (- )in p.u
b) A fault occurs at bus 4 of the network shown in Figure Q3. Pre-fault nodal voltages throughout the network are of 1 p.u. and the impedance of the electric arc is neglected. Sequence impedance parameters of the generator, transmission lines, and transformer are given in Figure Q3, where X and Y are the last two digits of your student number. jX(1) j0.1Y p.u. jX2)= j0.1Y p.u. jXko) = j0.1X p.u. V₁ = 120° p.u. V₂ = 120° p.u. (i) (ii) 0 jX(1) = j0.2 p.u. 1 jx(2) j0.2 p.u. 2 jX1(0) = j0.25 p.u. jXT(1) jXT(2) 종 3 j0.1X p.u. JX3(1) j0.1Y p.u. j0.1X p.u. JX3(2) j0.1Y p.u. jXT(0) j0.1X p.u. JX3(0)=j0.15 p.u. 0 = x = 1, jX2(1) j0.2Y p.u. V₁=1/0° p.u. jX(2(2) = j0.2Y p.u. jX2(0) = j0.3X p.u. = V3 = 120° p.u. Figure Q3. Circuit for problem 3b). For example, if your student number is c1700123, then: y = 7 = = jXa(r) = j0.13 p.u., jXa(z) = j0.13 p. u., and jXa(o) = j0.12 p. u. Assuming a balanced excitation, draw the positive, negative and zero sequence Thévenin equivalent circuits as seen from…
The one line diagram of a simple 3-bus power system shown below. All impedances are expresses in per unit on a common base. A three phase fault occurs at bus 3 through a fault impedance Z =j 0.19 pu, calculate the per unit fault current. A. 1.5 p.u. B.2.5 p.u. G₁ j 0.05 j0.75 j 0.3 3 C. 5.0 p.u. D. 3.0 p.u. G₂ j 0.075 j0.45 2
The sample power system subjected to three phase fault at bus 4. The system values are given below The faulted bus initial voltage = 1.0 p.u Z44 = 0.484p.u (Zbus value) Fault impedance Z;= 0.53p.u Fault current (le )in p.u
b) A fault occurs at bus 3 of the network shown in Figure Q4. Pre-fault nodal voltages throughout the network are of 1 p.u. and the impedance of the electric arc is neglected. Sequence impedance parameters of the generator, transmission lines, transformer and load are given in Figure Q4. V₁ = 120° p.u. V₂ = 120° p.u. V₂ = 1/0° p.u. V₂= 120° p.u. jXj0.1 p.u. JX2) 0.1 p.u. jX0j0.15 p.u. jXn-j0.2 p.u. 1 JX(2)-j0.2 p.u. 2 jX)=j0.25 p.u. JX20-10.15 p.u. jXa(z)-j0.2 p.u. 4 jX2(0)=j0.2 p.u. jXT(1) j0.1 p.u. jXT(2)=j0.15 p.u. jXT(0)=j0.1 p.u. Figure Q4. Circuit for problem 4b). = jXj0.1 p.u. j0.1 p.u. - JX(2) JXL(0) 10.1 p.u. = (i) Assuming a balanced excitation, draw the positive, negative and zero sequence Thévenin equivalent circuits as seen from bus 3. (ii) Determine the positive sequence fault current for the case when a three- phase-to-ground fault occurs at bus 3 of the network. (iii) Determine the short-circuit fault current for the case when a one-phase- to-ground fault occurs at bus…
The LLLG fault occurs at bus-6 with pre-fault voltage as 1.05 p.u. If the positive sequence impedance at bus-7 is j0.35 and positive sequence current is -j1.250. Find value of positive sequence voltage at bus-7.
The system values are given below. The bus 1 voltage after fault = 1.5 p.u The bus 2 voltage after fault = 1.2 p.u The line admittance between bus 1 and bus 2 (Y12 ) is = 0.8 p.u The post fault current current flow between bus 1 and 2 is ..............
b) A fault occurs at bus 2 of the network shown in Figure Q3. Pre-fault nodal voltages throughout the network are of 1 p.u. and the impedance of the electric arc is neglected. Sequence impedance parameters of the generator, transmission lines, and transformer are given in Figure Q3, where X and Y are the last two digits of your student number. JX20 /0.1X p.u. jXa2) 0.1X p.u. JX20 j0.2Y p.u. V,= 120° p.u. V, 120° p.u. V, 120° p.u. jX4-70.2X p.u. jX2 j0.2X p.u. jX o 0.2Y p.u. jXncay J0.25 p.u. jXna J0.25 p.u. 3 jXno0.3 p.u. jXTu) /0.2Y p.u. jXra j0.2Y p.u. - j0.2Y p.u. Xp-10.1X p.u. jXa j0.1X p.u. jXp0)- j0.05 p.u. 0 Figure Q3. Circuit for problem 3b). For example, if your student number is c1700123, then: jXac1) = j0.22 p.u., jXac2) = j0.22 p.u., and jXaco) = j0.23 p. u. X-2 Y=8 (iv) Determine the short-circuit fault current for the case when a phase-to- phase fault occurs at bus 2.
Q3: - A three-phase fault occurs at bus-1 of the network shown in figure below. The pre-fault voltage is 1.05 PU and the pre-fault load current is neglected. (45%) i) determine the bus impedance matrix. ii) calculate the sub-transient fault current and the contribution to the fault current from the transmission line. T1 T2 T.L j0.1 PU 10.1 PU j0.105 PU G jXdg j0.15 PU M jXdm $0.2 PU
b) A fault occurs at bus 4 of the network shown in Figure Q3. Pre-fault nodal voltages throughout the network are of 1 p.u. and the impedance of the electric arc is neglected. Sequence impedance parameters of the generator, transmission lines, and transformer are given in Figure Q3, where X and Y are the last two digits of your student number. V₁ = 120° p.u. V₂ = 120° p.u. jX(1) j0.1Y p.u. jX2)= j0.1Y p.u. jXko) j0.1X p.u. - 0 jX(1) = j0.2 p.u. 1JX(2) = 0.2 p.u. 2 jX1(0) = j0.25 p.u. jX2(1) j0.2 p.u. V₁=1/0° p.u. jX(2(2) = j0.2Y p.u. jX2(0) = j0.3X p.u. = V₂ = 120° p.u. jXT(1) j0.1X p.u. jXT(2) j0.1X p.u. JX3(1) j0.1Y p.u. JX3(2)=j0.1Y p.u. jXT(0) j0.1X p.u. JX3(0)=j0.15 p.u. 0- = 3 = Figure Q3. Circuit for problem 3b). For example, if your student number is c1700123, then: jXa(n) = j0.13 p. u., jXa(z) = j0.13 p. u., and jXa(o) = j0.12 p. u. 4 (i) Assuming a balanced excitation, draw the positive, negative and zero sequence Thévenin equivalent circuits as seen from bus 4. (ii)…