Most buses in a typical power-flow program are a.voltage controlled bus b.PQ bus c.PV bus d.Slack bus
Q: The load flow data for a three-bus system is given below. Taking bus 1 as the slack bus, determine…
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Q: For the following single line diagram of a three-phase system, a three-phase fault occurs at point P…
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Q: The following figure shows the single-line diagram of a three-bus power system. Additionally, a…
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Q: 23. A 10-bus power system consists of four generator buses indexed as G1, G2, G3, G4 and six load…
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Q: 4. A two-bus power system bus admittance matrix is bus -j9 j3 j3 -j8 53] P per unit. Suppose…
A: Note: We are authorized to answer three subparts at a time since you have not mentioned which part…
Q: For the following single line diagram of a three-phase system, a three-phase fault occurs at point P…
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Q: In a 7-bus system, the double line fault is occurred at bus -5. During fault the positive sequence…
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Q: Problem 5 Thevenin equivalent sequence networks looking into the faulted bus of a power system are…
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Q: As shown in Figure 1, a synchronous generator and motor are rated 100 MVA, 13.8 kV.??"=0.2per unit,…
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Q: 5. The zero-, positive-, and negative-sequence bus impedance matrices for a three-bus power system…
A: “Since you have posted a question with multiple sub-parts, we will solve first three sub-parts for…
Q: V, =1.025Z0°pu P=300MW j0.05 Bus 1 Bus 3 V = 1.03 Slack j0.025 j0.025 Bus 2 400MW 200MVAR
A: The given power system can be redrawn as shown below:
Q: The one line diagram of a simple three bus power system is shown in figure Each generator is…
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A: We are authorized to answer three one question at a time, since you have not mentioned which part…
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Q: The load flow data for a three-bus system is given below. Taking bus 1 as the slack bus, determine…
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Q: Which of the following is the busbar type where active power and busbar voltage are input data in…
A: type of bus quantities specified quantities unspecified Generator bus P, V Q, δ Load bus P, Q V,…
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A: According to the question we have, Develop an expression, in terms of the generated e.m.f. and the…
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Q: For the following single line diagram of a three-phase system, a three-phase fault occurs at point P…
A: Given data : G1 = 20mvA = 6.9kv which is taken as base value Xg1 = 0.15 pXg2 at new Base =…
Q: The synchronous generator in the given figure is operating at rated MVA, 0.75 pf lagging and at 8%…
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Q: Contribution of fault analysis in power system netwrok?
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A:
- Most buses in a typical power-flow program are
a.voltage controlled bus
b.PQ bus
c.PV bus
d.Slack bus
2-The power-flow problem is the computation of voltage magnitude and phase angle at each bus in a power system under balanced three-phase steady-state conditions.
- False
- True
3-The following sequence currents were recorded in a power system under a fault condition Ipositive=j1.5pu, Inegative=–j0pu, Izero=– j0pu. The fault is
a.Three-phase
b.Double Line to ground
c.Line to ground
d.Line to line
4-
- he following sequence currents were recorded in a power system under a fault condition Ipositive=j1.5pu, Inegative=j0pu, Izero=j0pu. The fault is
a.Three-phase
b.Double Line to ground
c.Line to ground
d.Line to line
i uploded the houndots (book )here :https://seomidea.com/hct/nu.pdf
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- b) A fault occurs at bus 4 of the network shown in Figure Q3. Pre-fault nodal voltages throughout the network are of 1 p.u. and the impedance of the electric arc is neglected. Sequence impedance parameters of the generator, transmission lines, and transformer are given in Figure Q3, where X and Y are the last two digits of your student number. jX(1) j0.1Y p.u. jX2)= j0.1Y p.u. jXko) = j0.1X p.u. V₁ = 120° p.u. V₂ = 120° p.u. (i) (ii) 0 jX(1) = j0.2 p.u. 1 jx(2) j0.2 p.u. 2 jX1(0) = j0.25 p.u. jXT(1) jXT(2) 종 3 j0.1X p.u. JX3(1) j0.1Y p.u. j0.1X p.u. JX3(2) j0.1Y p.u. jXT(0) j0.1X p.u. JX3(0)=j0.15 p.u. 0 = x = 1, jX2(1) j0.2Y p.u. V₁=1/0° p.u. jX(2(2) = j0.2Y p.u. jX2(0) = j0.3X p.u. = V3 = 120° p.u. Figure Q3. Circuit for problem 3b). For example, if your student number is c1700123, then: y = 7 = = jXa(r) = j0.13 p.u., jXa(z) = j0.13 p. u., and jXa(o) = j0.12 p. u. Assuming a balanced excitation, draw the positive, negative and zero sequence Thévenin equivalent circuits as seen from…Consider the system shown in the single-line diagram of Figure (3). All reactances are shown in per unit to the same base. Assume that the voltage at both sources is 1 p.u. a Find the fault current due to a bolted- three-phase short circuit at bus 3 b- Find the fault current supplied by each generator and the voltage at each of the buses 1 and 2 under fault conditions 0.06 p.u. 0.2 p.u. 0.04 p.u. 0.25 p.u. 0.2 p.u. 0.2 p.. 0.2 p.u. 0.06 p.u. 0.25 p.u. Figure (3) Single-line diagram ele ver ele 888 ele 0.06 p.u. 0.25 p.u.The system values are given below. The bus 1 voltage after fault = 1.5 p.u The bus 2 voltage after fault = 1.2 p.u The line admittance between bus 1 and bus 2 (Y12 ) is = 0.8 p.u The post fault current current flow between bus 1 and 2 is ..............
- The one line diagram of a simple 3-bus power system shown below. All impedances are expresses in per unit on a common base. A three phase fault occurs at bus 3 through a fault impedance Z =j 0.19 pu, calculate the per unit fault current. A. 1.5 p.u. B.2.5 p.u. G₁ j 0.05 j0.75 j 0.3 3 C. 5.0 p.u. D. 3.0 p.u. G₂ j 0.075 j0.45 2b) A fault occurs at bus 3 of the network shown in Figure Q4. Pre-fault nodal voltages throughout the network are of 1 p.u. and the impedance of the electric arc is neglected. Sequence impedance parameters of the generator, transmission lines, transformer and load are given in Figure Q4. V₁ = 120° p.u. V₂ = 120° p.u. V₂ = 1/0° p.u. V₂= 120° p.u. jXj0.1 p.u. JX2) 0.1 p.u. jX0j0.15 p.u. jXn-j0.2 p.u. 1 JX(2)-j0.2 p.u. 2 jX)=j0.25 p.u. JX20-10.15 p.u. jXa(z)-j0.2 p.u. 4 jX2(0)=j0.2 p.u. jXT(1) j0.1 p.u. jXT(2)=j0.15 p.u. jXT(0)=j0.1 p.u. Figure Q4. Circuit for problem 4b). = jXj0.1 p.u. j0.1 p.u. - JX(2) JXL(0) 10.1 p.u. = (i) Assuming a balanced excitation, draw the positive, negative and zero sequence Thévenin equivalent circuits as seen from bus 3. (ii) Determine the positive sequence fault current for the case when a three- phase-to-ground fault occurs at bus 3 of the network. (iii) Determine the short-circuit fault current for the case when a one-phase- to-ground fault occurs at bus…Q3: - A three-phase fault occurs at bus-1 of the network shown in figure below. The pre-fault voltage is 1.05 PU and the pre-fault load current is neglected. (45%) i) determine the bus impedance matrix. ii) calculate the sub-transient fault current and the contribution to the fault current from the transmission line. T1 T2 T.L j0.1 PU 10.1 PU j0.105 PU G jXdg j0.15 PU M jXdm $0.2 PU
- b) A fault occurs at bus 4 of the network shown in Figure Q3. Pre-fault nodal voltages throughout the network are of 1 p.u. and the impedance of the electric arc is neglected. Sequence impedance parameters of the generator, transmission lines, and transformer are given in Figure Q3, where X and Y are the last two digits of your student number. V₁ = 120° p.u. V₂ = 120° p.u. jX(1) j0.1Y p.u. jX2)= j0.1Y p.u. jXko) j0.1X p.u. - 0 jX(1) = j0.2 p.u. 1JX(2) = 0.2 p.u. 2 jX1(0) = j0.25 p.u. jX2(1) j0.2 p.u. V₁=1/0° p.u. jX(2(2) = j0.2Y p.u. jX2(0) = j0.3X p.u. = V₂ = 120° p.u. jXT(1) j0.1X p.u. jXT(2) j0.1X p.u. JX3(1) j0.1Y p.u. JX3(2)=j0.1Y p.u. jXT(0) j0.1X p.u. JX3(0)=j0.15 p.u. 0- = 3 = Figure Q3. Circuit for problem 3b). For example, if your student number is c1700123, then: jXa(n) = j0.13 p. u., jXa(z) = j0.13 p. u., and jXa(o) = j0.12 p. u. 4 (i) Assuming a balanced excitation, draw the positive, negative and zero sequence Thévenin equivalent circuits as seen from bus 4. (ii)…In a 7-bus system, the double line fault is occurred at bus -5. During fault the positive sequence potential difference between the bus-4 and bus-1is found to be 0.0175. what is the line impedance which is connected between bus-4 and bus-1 if the current flowing through transmission line is -j 0.148? Select one: O a. -jo.182 O b. +j0.1182 O c. -jo.1182 O d. +j0.182b) The one-line diagram for a simple power system is given in Figure 1(b). į. Draw the impedance diagram of the system. i. Construct the bus admittance matrix, Xeus and bus impedance matrix, Zous of the system. I. Evaluate the fault current, bus voltages and line current during the flow when a balanced three-phase fault occurs on bus 1. bus 1 bus 2 j65 N G G 25 MVA 25 MVA 13.8 kV 15% 13.2/69 kV 11% 25 MVA 69/13.2 kV 11% 15 MVA 13 kV 15% Figure 1(b) m
- Q2\ The one-line diagram of a simple power system is shown in figure below. All impedances are expressed in per unit (pu) on a common MVA base. All resistances and shunt capacitances are neglected. The generators are operating on no load at their rated voltage. A three-phase fault occurs at bus 1 through a fault impedance of Zf = j0.08 per unit. Using Thevenin's theorem obtain the impedance to the point of fault and the fault current in per unit. Determine the bus voltages and line currents of generators during fault. X₁ = = 0.1 XT-0.1 3 1 to ojo XL=0.2 2 040 X₁ = 0.1b) A fault occurs at bus 2 of the network shown in Figure Q3. Pre-fault nodal voltages throughout the network are of 1 p.u. and the impedance of the electric arc is neglected. Sequence impedance parameters of the generator, transmission lines, and transformer are given in Figure Q3, where X and Y are the last two digits of your student number. JX20 /0.1X p.u. jXa2) 0.1X p.u. JX20 j0.2Y p.u. V,= 120° p.u. V, 120° p.u. V, 120° p.u. jX4-70.2X p.u. jX2 j0.2X p.u. jX o 0.2Y p.u. jXncay J0.25 p.u. jXna J0.25 p.u. 3 jXno0.3 p.u. jXTu) /0.2Y p.u. jXra j0.2Y p.u. - j0.2Y p.u. Xp-10.1X p.u. jXa j0.1X p.u. jXp0)- j0.05 p.u. 0 Figure Q3. Circuit for problem 3b). For example, if your student number is c1700123, then: jXac1) = j0.22 p.u., jXac2) = j0.22 p.u., and jXaco) = j0.23 p. u. X-2 Y=8 (iv) Determine the short-circuit fault current for the case when a phase-to- phase fault occurs at bus 2.Q1/ for the four-bus power system shown in figure 1, the positive, negative and zero sequence impedances of generators and transformers are listed in table 1. The impedances of transmission lines are indicated on the figure in per unit. Assuming the Sb=200MVA, and Vb=11kV. Find the fault and generators currents when: Line to line fault occurs in bus 3. 2. Line to ground fault occurs in bus 4 through impedance of j0.1 py. 1. (2) S-100+j70 T1 1) j0.21 T2 小小 G2 j0.1 j0.22 j0.13 3) S=90+j30 T3 G3 S-160+j110 j0.18 j0.1 X' X" x° G1 0.2 0.2 0.04 G2 0.15 0.2 0.05 G3 0.25 0.25 0.07 T1 0.05 0.05 0.05 T2 0.04 0.04 0.04 T3 0.043 0.043 0.043