= the relationship and the is typically written RT 8.314 J/mol. K), quency factor, and or the reaction. m of this equation -1/2) alent to e constants for a ent absolute ▾ Part A The activation energy of a certain reaction is 42.1 kJ/mol. At 20 °C, the rate constant is 0.0150s¹ At what temperature in degrees Celsius would this reaction go twice as fast? Express your answer with the appropriate units. AM T₂ Value Submit Request Answer Part B Units Given that the initial rate constant is 0.0150s¹ at an initial temperature of 20 °C, what would the rate constant be at a temperature of 200. °C for the same reaction described in Part A?

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The Arrhenius equation shows the relationship
between the rate constant k and the
temperature T in kelvins and is typically written
as
k = Ae-E/RT
where R is the gas constant (8.314 J/mol K),
A is a constant called the frequency factor, and
Da is the activation energy for the reaction.
However, a more practical form of this equation
IS
In = (1-12)
Ea
R
which is mathmatically equivalent to
In
Ea
F (1/2
R
T₂
k2
T1
where ki and k2 are the rate constants for a
single reaction at two different absolute
temperatures (T₁ and T₂).
▼
Part A
The activation energy of a certain reaction is 42.1 kJ/mol. At 20 °C, the rate constant is 0.0150s¹. At what
temperature in degrees Celsius would this reaction go twice as fast?
Express your answer with the appropriate units.
T₂ =
Submit
Part B
Value
k₂ =
Request Answer
Submit
Given that the initial rate constant is 0.0150s¹ at an initial temperature of 20 °C, what would the rate constant
be at a temperature of 200. °C for the same reaction described in Part A?
Express your answer with the appropriate units.
Value
Units
Request Answer
Units
By
P Pearson
?
PEAK
?
Transcribed Image Text:The Arrhenius equation shows the relationship between the rate constant k and the temperature T in kelvins and is typically written as k = Ae-E/RT where R is the gas constant (8.314 J/mol K), A is a constant called the frequency factor, and Da is the activation energy for the reaction. However, a more practical form of this equation IS In = (1-12) Ea R which is mathmatically equivalent to In Ea F (1/2 R T₂ k2 T1 where ki and k2 are the rate constants for a single reaction at two different absolute temperatures (T₁ and T₂). ▼ Part A The activation energy of a certain reaction is 42.1 kJ/mol. At 20 °C, the rate constant is 0.0150s¹. At what temperature in degrees Celsius would this reaction go twice as fast? Express your answer with the appropriate units. T₂ = Submit Part B Value k₂ = Request Answer Submit Given that the initial rate constant is 0.0150s¹ at an initial temperature of 20 °C, what would the rate constant be at a temperature of 200. °C for the same reaction described in Part A? Express your answer with the appropriate units. Value Units Request Answer Units By P Pearson ? PEAK ?
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