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The reaction of sodium borohydride with ketones proceeds rapidly at room temperature, forming an intermediate borate ester which is hydrolyzed to give the product alcohol: 

4 R2C=O + Na+BH4-    --->     (R2CHO)4B-Na+

(R2CHO)4B-Na+   + 2H2O ---> 4R2CHOH + Na+BO2-

Rewrite these two steps using benzil as the ketone, and using structural formulas throughout, rather than the condensed forms above.

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