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The radius of a calcium atom is approximately 0.23 nm. What is the ionization energy?
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- The radius of a calcium atom is approximately 0.23 nm. What is the magnitude of the ionization energy? Express your answer in joules.The radius of a cadmium atom is approximately 0.16 nm. What is the ionization energy?B. A laser with power output of 2.0 mW at a wavelength of 400 nm is projected onto a Calcium metal. The binding energy is 2.31 eV. i. How many electrons per second are ejected? i. What power is carried away by the electrons?
- The energy required to break one bond in DNA is 10^−20J. This value in eV is nearly ?The two nuclei in the carbon monoxide (CO) molecules are 0.1128 nm apart. The mass of the carbon atom is 1.993x10-26 kg. The mass of the oxygen atom is 2.656x10-26 kg. Spectroscopic measurements show that adjacent vibrational energy levels for the CO molecule are 0.269 eV. What is the effective spring constant of the CO molecule? (Give your answer in N/m.)Q4. Calculate the values of electron and hole concentrations in cm³ at 300 K for intrinsic Ge, Si and GaAs, given: Quantity me/mo m/mo Eg (eV) mo e kB h Ge 0.55 0.31 0.66 9.1×10-³1 kg 1.6×10-¹9 C 1.38×10-23 J/K 1.054×10-34 Js Si 1.10 0.56 1.12 Ge 0.068 0.500 1.43
- The two nuclei in the carbon monoxide (CO) molecules are 0.1128 nm apart. The mass of the carbon atom is 1.993x10-26 kg. The mass of the oxygen atom is 2.656x10-26 kg. What is the first excited rotational energy level for the CO molecule? (Give the your answer in meV.)For magnesium, the first ionization potential is 7.6 eV. The second ionization potential (additional energy required to remove a second electron) is almost twice this, 15 eV, and the third ionization potential is much larger, about 80 eV. How can these numbers be understood?Which of these expressions would yield the wavelength of light in meters emitted when an electron drops from orbit n=3 n=2 in a Bohr hydrogen atom? Given h=4.14 x 10^15 eVs and c=3.00 x 10^8 m/s. A. 1.89 x h x c B. hc/1.89 C. 1.89/hxc D. (1.51+ 3.4)/hc E. hc/3.4
- a. The electron of a hydrogen atom is excited into a higher energy level from a lower energy level. A short time later the electron relaxes down to the no = 1 energy level, releasing a photon with a wavelength of 93.83 nm. Compute the quantum number of the energy level the electron relaxes from, nhi. Note: the Rydberg constant in units of wavenumbers is 109,625 cm-1 nhi =16 b. What would the wavenumber, wavelength and energy of the photon be if instead no = 1 and nhi = 4? V: 6.9121e14 x (cm-¹) λ: (nm) E: 45.8e-20 ✓ (1)6. A solid at temperature is placed in an external magnetic field B = 1 Tesla = 1 × 10¹ gauss. The solid contains weakly interacting paramagnetic atoms of spin 1/2, so that the energy of each atom is ±μB. a. If the magnetic moment is equal to one Bohr magneton, i.e., μ = h x 1.4 MHz/gauss, below what temperature must one cool the solid so that more than 75% of the atoms are polarized with their spins parallel to the external magnetic field? b. Suppose that one considered instead a solid which is free of paramagnetic atoms but contains many protons (e.g., paraffin). Each proton has spin 1/2 and a magnetic moment µp = h x 2.1 kHz/gauss. At the same temperature as you determined in part a., what fraction of protons will have their spins aligned parallel to the external magnetic field?Which of these expressions would yield the wavelength of light in meters emitted when an electron drops from orbit n = 3 to n = 2 in a Bohr hydrogen atom? Given h = 4.14 x 10-15 eVs and c = 3.00 x 108 m/s. a. 1.89/hxc b. hc/1.89 c. 1.89 x h x c d. (1.51 + 3.4)/hc e. hc/3.4