please help with these questions. please show work, thank you! 84The pressures deep within the Earth are much greater than those on the surface, and to make use of thermochemical data in geochemical assessmentswe need to take the differences into account.Given that the enthalpy of combustion of graphite is-393.50 kJ mol and that of diamond is-395.41 kJ mol, calculate the standard enthalpy kmol-¹) of the transition:C(s. graphite)-C (s, diamond).Type your answer...HNO3+ type your answer...NOCu type your answer...type your answer..type your answer...Make sure the stoichiometry coefficients you input are in the simplest form type your answer.the reaction.CulNoly type your answertype your answer...Mn2 type your answer...CF type your answer...type your answer.Make sure the stoichiometry coefficients you input are in the simplest form type your answer...partionSubmitOH type your answeCIO type your answer.H₂Omol electrons are transferred per mile ofH₂O+tvMOmol electrons are transferred per me of What is the enthalpy change for per mole of the following reaction (in kJ mol ¹You may need the data below:2H₂+1₂-2 HigThe previous reaction is exothermic.TrueFalseSingle bonds Bond Energy (kJ mol )H-H432149295HH-IJust in case you didn't remember, bond energy (B.E) is the energy to break the corresponding bonds into free atomsOr, B.Ex-y corresponds to the reaction X-Y(g)-X-(g) +YType your answer.tv alo

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The pressures deep within the Earth are much greater than those on we need to take the differences into account. the surface, and to make use of thermochemical data in geochemical assessments Given that the enthalpy of combustion of graphite is-393.50 kJ mol 1 and that of diamond is-395.41 kJ mol", calculate the standard enthalpy ( mol-¹) of the transition: C(s, graphite)-C (s, diamond).

The pressures deep within the Earth are much greater than those on we need to take the differences into account. the surface, and to make use of thermochemical data in geochemical assessments Given that the enthalpy of combustion of graphite is-393.50 kJ mol 1 and that of diamond is-395.41 kJ mol", calculate the standard enthalpy ( mol-¹) of the transition: C(s, graphite)-C (s, diamond).

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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I know you don't answer graded questions and I am not looking for you to straight up give me the answer to this but how do I even start? like I said before I know that the highest peak is 16amu which is Oxygen but do I just the vertical bar as a ratio? Like the next bar to the left (15amu?) is like 90% intensity? so like 9:10 ratio? There isn't even a 15amu element so please just give me some idea where to start. The place in the book it tells you to go to read has nothing about this stuff, its about finding empirical formulas from mass or percentages.... please help me!
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