The potential in a region between x = 0 and x = 6.00 m is V = a + bx, where a = 15.2 V and b = -3.50 V/m. a) Determine the potential at x= 0, x= 3.00 m, and x= 6.00 m. b) Determine the magnitude (Vm) and direction of the electric field at x= 0, x= 3.00 m, and x= 6.00 m.

The potential in a region between x = 0 and x = 6.00 m is V = a + bx, where a = 15.8 V and b = -6.70 V/m. (a) Determine the potential at x = 0. V Determine the potential at x = 3.00 m. V Determine the potential at x = 6.00 m. V (b) Determine the magnitude and direction of the electric field at x = 0. V/m magnitude direction |---Select--- ✓ Determine the magnitude and direction of the electric field at x = 3.00 m. magnitude V/m direction ---Select--- ✓ Determine the magnitude and direction of the electric field at x = 6.00 m. magnitude V/m direction --Select--- ✓

The potential in a region between x = 0 and x = 6.00 m is V = a + bx, where a = 20.0 V and b = -6.50 V/m. (a) Determine the potential at x = 0. V Determine the potential at x = 3.00 m. Determine the potential at x = 6.00 m. V (b) Determine the magnitude and direction of the electric field at x = 0. V/m magnitude direction ---Select--- Determine the magnitude and direction of the electric field at x = 3.00 m. magnitude V/m direction ---Select--- O Determine the magnitude and direction of the electric field at x = 6.00 m. magnitude V/m direction --Select---

Problem 18:   The electric potential in a certain region is given by the equation V(x,y,z) = 3αx2y3 - 2γx2y4z2 where the potential is in volts when the positions are given in meters.  Part (d)  The constants in this equation are α = 5.2 V/m5 and γ = 1.39 V/m8. Using this information, calculate the magnitude of the electric field at the point (x1,y1,z1) = (-5.0, 2.0, 1.5) m in units of newtons per coulomb.