An air-filled parallel-plate capacitor has plates of area 2.10 cm2 separated by 2.00 mm. The capacitor is connected to a(n) 11.0 V battery. (a) Find the value of its capacitance. pF (b) What is the charge on the capacitor? pC (c) What is the magnitude of the uniform electric field between the plates? N/C

Two parallel plates have equal and opposite charges. When the space between the plates is evacuated, the electric field is E= 3.30×105 V/m. When the space is filled with dielectric, the electric field is E= 2.50×105 V/m. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Energy density, both before and after the. What is the charge density on each surface of the dielectric? Express your answer in coulombs per meter squared. να ΑΣΦ ? |X| X•10" |oi| = C/m²

A parallel-plate capacitor has capacitance C0 = 8.00 pF when there is air between the plates. The separation between the plates is 1.20 mm. Express your answer with the appropriate units. Part A: What is the maximum magnitude of charge that can be placed on each plate if the electric field in the region between the plates is not to exceed 3.00×104 V/m? Part B: A dielectric with K = 2.70 is inserted between the plates of the capacitor, completely filling the volume between the plates. Now what is the maximum magnitude of charge on each plate if the electric field between the plates is not to exceed 3.00×104 V/m?

Extra: How is the dielectric constant defined relative to Eplates, Edielectric, and/or Enet?