An air-filled parallel-plate capacitor has plates of area 2.60 cm² separated by 2.50 mm. The capacitor is connected to a 15.0-V battery. (a) Find the value of its capacitance. pF (b) What is the charge on the capacitor? pC (c) What is the magnitude of the uniform electric field between the plates? V/m

A parallel-plate capacitor has capacitance C0 = 8.00 pF when there is air between the plates. The separation between the plates is 1.20 mm. Express your answer with the appropriate units. Part A: What is the maximum magnitude of charge that can be placed on each plate if the electric field in the region between the plates is not to exceed 3.00×104 V/m? Part B: A dielectric with K = 2.70 is inserted between the plates of the capacitor, completely filling the volume between the plates. Now what is the maximum magnitude of charge on each plate if the electric field between the plates is not to exceed 3.00×104 V/m?

Extra: How is the dielectric constant defined relative to Eplates, Edielectric, and/or Enet?

A parallel-plate capacitor is constructed using a dielectric material whose dielectric constant is 3.30 and whose dielectric strength is 1.20 x 108 V/m. The desired capacitance is 0.300 μF, and the capacitor must withstand a maximum potential difference of 4.00 kV. Find the minimum area of the capacitor plates. m²

An electron is released from rest at the negative plate of a parallel plate capacitor and accelerates to the positive plate (see the drawing). The plates are separated by a distance of 1.7 cm, and the electric field within the capacitor has a magnitude of 2.8 x 106 V/m. What is the kinetic energy of the electron just as it reaches the positive plate? Electric field Electron KE positive + + + + + + + +

Ex (N/C) Exs -Exs 2 3 4 5 6 x (m) The graph shows the electric field as a function of position in a particular region of space. If Exs = 400 difference between x = 0.00 m and x = 2.00 m? what is the potential m i V

1. What is the capacitance of a parallel plate capacitor with metal plates, each of area 1.00 m², separated by 2.00 mm? What charge is stored in this capacitor if a voltage of 3.00 x 103 V is applied to it? 2. The capacitors have values C1 = 2.0 µF and C2 = 4.0 µF, C3 = 5.0 µF C4 = 7.0 µF and the potential difference across the battery is 9.0 V. Assume that the capacitors are connected in series. a) Find the equivalent capacitance of the circuit. b) Solve for the potential difference across each capacitors. 3. Given the same problem in #2. Assume that the capacitors are connected in parallel. a) Find the equivalent capacitance of the circuit. b) Solve for the charge across each capacitors.

A parallel plate capacitor has a capacitance of 110. pF and a plate area of 100. cm2. The space between the plates is filled with mica whose dielectric constant is 5.40. The plates of the capacitor are kept at 40.0 V. a) What is the strength of the electric field in the mica?  b) What is the amount of free charge on the plates? show complete solution

An air-filled parallel-plate capacitor has plates of area 2.50 cm^2 separated by 1.80 mm. The capacitor is connected to a(n) 13.0 V battery. a) Find the value of its capacitance. pF b) What is the charge on the capacitor? pC c) What is the magnitude of the uniform electric field between the plates? N/C

Consider a parallel-plate capacitor having an area of 2550 mm^2 and a plate separation of 4.9mm and with a material of dielectric constant 5.9 positioned between the plates. Also, the value of E0 is 8.85x10^-12F/m. a) What is the capacitance of this capacitor in pF? b) compute the electric field that must be applied for a charge pf 7.8x10^-8C to be stored on each plate in V/m.