The pka's of the ascorbic acid are pka1 = 4.10 and pka2 = 11.80. If the net charge of ascorbic acid is exactly -1, what is the pH of the solution? Use 2 decimal places.

Note these acronyms: HOAC = Acetic Acid; NaOAc = Sodium Acetate; THF = tetrahydrofuran Ph = Phenyl = C6H5; DMSO = Dimethyl Sulfoxide, H3C-0-H = methanol, Zn = Zinc, D = heavy Hydrogen (1 proton and 1 neutron). Acetone = Acetic Acid = THF= Ph= H3C CH3 H3C HO, 1. Write the products of the following reactions. If there is no reaction write NR. For full credit clearly indicate cis or trans relationships in cyclic compounds, where appropriate. 1) Н.В ТHF 2) HOOH, NaOH water solvent j) CH 1)H B-THF 2) НООН, N:OH water solvent k) 1)Ozuue 2) (CH ),S CH3 1) Ozcne 2) CH,),S

thank you, I would like to have a follow-up question.  Would you get an answer of 4.05 pH if the value of your formic acid is 0.050 M while your sodium formate is 0.10 M? and still the same pKa which is 3.75?

Answer to question 20 please