A 20 ml solution of 0.1 M glycine hydrochloride has been prepared. How many moles of the weak acid and conjugate base forms of glycine are present after the addition of 620 ul of 1.0 M NaOH? What is the pH of the resulting solution?

Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter15: Acid–base Equilibria
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A 20 ml solution of 0.1 M glycine hydrochloride has been prepared. How many moles of the
weak acid and conjugate base forms of glycine are present after the addition of 620 µl of 1.0 M
NaOH? What is the pH of the resulting solution?
Transcribed Image Text:A 20 ml solution of 0.1 M glycine hydrochloride has been prepared. How many moles of the weak acid and conjugate base forms of glycine are present after the addition of 620 µl of 1.0 M NaOH? What is the pH of the resulting solution?
Expert Solution
Step 1

Given, 

Molarity of glycine hydrochloride (say HA) = 0.1 M 

Volume of glycine hydrochloride = 20 mL 

Molarity of NaOH = 1.0 M 

Volume of NaOH = 620 µL 

What is the pH of the resulting solution = ? 

 

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