The pedigree table below shows the blood types of three generations of family members. Notice that some of the blood type phenotypes have been given to you. What is the genotype of the individuals 1-6? Give the probable genotype of all other family members. AB 5 6. AB 2.

The pedigree table below shows the blood types of three generations of family members. Notice that some of the blood type phenotypes have been given to you. What is the genotype of the individuals 1-6? Give the probable genotype of all other family members. AB 5 6. AB 2.

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Description: The pedigree table below shows the blood types of three generations of family members. Notice thatsome of the blood type phenotypes have been given to you. What is the genotype of the individuals 1-6?Give the probable genotype of all other family me

Human Biology (MindTap Course List)

11th Edition

ISBN:9781305112100

Author:Cecie Starr, Beverly McMillan

Publisher:Cecie Starr, Beverly McMillan

Chapter19: Introduction To Genetics

Section: Chapter Questions

Problem 3SQ

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The ABO blood system has been used to settle cases of disputed paternity. Suppose, as a geneticist, you must testify during a case in which the mother has type A blood, the child has type O blood, and the alleged father has type B blood. How would you respond to the following statements? a. Mans attorney: The mother has type A blood, so the childs type O blood must have come from the father. Because my client has type B blood, he could not be the father. b. Mothers attorney: Further tests prove this man is heterozygous, so he must be the father.
A couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. What is the chance that this couple will have a child with two copies of the dominant mutant gene? What is the chance that the child will have normal height?
A couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. Should the parents be concerned about the heterozygous condition as well as the homozygous mutant condition?
Achondroplasia is a rare dominant autosomal defect resulting in dwarfism. The unaffected brother of an individual with achondroplasia is seeking counsel on the likelihood of his being a carrier of the mutant allele. What is the probability that the unaffected client is carrying the achondroplasia allele?
A single allele gives rise to the HbS form of hemoglobin. Individuals who are homozygous for the allele HbS/HbS develop sickle-cell anemia Section 9.5. Heterozygous individuals HbA/ HbS have few Symptoms. A couple who are both heterozygous for the HbS allele plan to have children. For each of the pregnancies, determine the probability that their child will be: a. homozygous for the HbS allele b. homozygous for the normal allele HbA c. heterozygous: HbA/HbS
Figure 8.10 In pea plants, purple flowers (P) are dominant to white (p), and yellow peas (Y) are dominant to green (y). What are the possible genotypes and phenotypes for a cross between PpYY and ppYy pea plants? How many squares would you need to complete a Punnett square analysis of this cross?
For each of the terms in the left column, choose thebest matching phrase in the right column.a. phenotype 1. having two identical alleles of a given geneb. alleles 2. the allele expressed in the phenotype ofthe heterozygotec. independent 3. alternate forms of a gene assortmentd. gametes 4. observable characteristice. gene 5. a cross between individuals bothheterozygous for two genesf. segregation 6. alleles of one gene separate into gametesrandomly with respect to alleles of othergenesg. heterozygote 7. reproductive cells containing only onecopy of each geneh. dominant 8. the allele that does not contribute to thephenotype of the heterozygotei. F1 9. the cross of an individual of ambiguousgenotype with a homozygous recessiveindividualj. testcross 10. an individual with two different allelesof a genek. genotype 11. the heritable entity that determines acharacteristicl. recessive 12. the alleles an individual hasm. dihybrid cross 13. the separation of the two alleles of agene into…
ABO Blood TypeThe following pedigree shows the incidence of ABO blood types in a family. dentify the genotypes of the following individuals: Individual Genotype II-1 II-2 II-4 II-5 III-2 III-3
The pedigree shows individual 1 and 2
Please answer all of them, they are all connected. PEDIGREE ANALYSIS and SYMBOLOGY: Examine the pedigree which has X linked Dominant inheritance of disorder. Use letter X* (asterisk denotes disorder) as genotype of the individuals which can be XX, XY, X*X*, X*X and X*Y. a. What is the genotype of IV-6? b. What is the genotype of III-6? c. What is the genotype of II-3? d. What is the genotype of III-8? e. If couple I-1 and I-2 will have a son, what is the probability of having the disorder? f. If couple III-8 and III-9 will have another child, what is the probability of having the disorder? g. Theoretically, if individual IV-3 and individual IV-5 will marry and will have a child, what is the probability of having a child without the X-linked disorder?
Please consider the pedigree below. There are no cases of false paternity. I B II A 2 3 III AB (A IV в 1 a. Which individual/s definitely has/have Bombay phenotype in the descendants of I-1 and I-2? b. What are the genotypes of individuals II-2 and III-2 at the ABO and H loci?
Place each box in the appropriate column. (Each box is used only once.) Probability of offspring homozygous recessive for the R gene is 25%. Phenotypic ratio of the progeny will be 1.1. SS Rrx SS rr The chance of Ss Rr offspring is 25%. Probability of an ss Rr offspring is 25%. Probability of an SS offspring is 100%. Phenotypic ratio of the progeny will be 9.3.3:1. Ss RR x Ss rr Genotypic ratio of the progeny will be 1:2:1. Probability of an SS Rr offspring is 50% Ss Rrx Ss Rr