The pedigree below shows a family of whom several members exhibit a genetic disorder. All the shaded symbols represent the individuals that inherited the trait. Which statement best represents the genotype of the mother in the P generation? A She carries both the recessive and dominant allele for the trait. B She carries two dominant alleles for the trait. She carries two recessive alleles for the trait. D She carries no alleles at all for the trait. 3.
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- In sweet pea plant, an allele for purple flowers (P) is dominant when paired with a recessive allele for red flowers (p). An allele for long pollen grains (L) is dominant when paired with a recessive allele for round pollen grain (l). Bateson and Punnett crossed a plant having purple flowers/long pollen grains with one having white/flowers/round pollen grains. All F1 offspring had purple flowers and long pollen grains. Among the F2 generation, the researchers observed the following phenotypes: 296 purple flowers/long pollen grains 19 purple flowers/round pollen grains 27 red flowers/long pollen grains 85 red flowers/round pollen grains What is the best explanation for these results?The comb shape of chickens is an example of an interesting inheritance pattern. Two genes, each with a dominant and recessive allele, determine comb phenotypes as follows: Comb Shape Description Genotype Single Comb homozygous recessive for both r and p rrpp Walnut comb both dominant alleles are present; R and P alleles are present R_P_ Pea comb the dominant allele P is present and the dominant allele R is absent rrP_ Rose comb the dominant allele R is present and the dominant allele P is absent R_pp Which of the following represents the correct phenotypes of the F2 offspring? Select one: a. Phenotype Single Walnut Pea Rose 9/16 3/16 3/16 1/16 b. Phenotype Single Walnut Pea Rose 3/16 1/16 9/16 3/16 c. Phenotype Single Walnut Pea Rose 1/16 9/16 3/16 3/16 d. Phenotype Single Walnut Pea Rose 3/16 9/16 1/16 3/16The comb shape of chickens is an example of an interesting inheritance pattern. Two genes, each with a dominant and recessive allele, determine comb phenotypes as follows: Comb Shape Description Genotype Single Comb homozygous recessive for both r and p rrpp Walnut comb both dominant alleles are present; R and P alleles are present R_P_ Pea comb the dominant allele P is present and the dominant allele R is absent rrP_ Rose comb the dominant allele R is present and the dominant allele P is absent R_pp If the P1 generation is a rose comb (RRpp) crossed with a pea comb (rrPP), which of the following represents the correct genotype and phenotype of the F1 offspring? Select one: a. Genotype Phenotype RRPP Single comb b. Genotype Phenotype RrPp walnut comb c. Genotype Phenotype RrPp pea comb d. Genotype Phenotype RRPP walnut comb
- Suppose there are four newly discoverecd genes, each with two allcles, in humans that all follow a simple Mendelian inheritance pattern. Alleles are noted by a + or- for dominant and recessive, respectively. The genes and their phenotypes are listed in the table. Gene Recessive Phenotype Dominant Phenotype Wiz have the ability to cast spells cannot cast spells Serp can communicate with snakes cannot talk to snakes have the ability to travel through time experience normal time Time Drgn have the ability to hatch dormant dragon eggs cannot hatch dragon eggs What is the probability of two completely heterozygous parents having a child with a Wiz Wiz Serp Serp genotype or a child with a Wiz Wiz Serp Serp genotype? Enter your answer as a decimal. genotype probability 口 17°C ) a 202 acer HUAWEI P30 lite TRIPLE CAMERAThis pedigree (below) shows inheritance of a genetic disorder in a family. Assume the trait is rare. What is the mode of inheritance for this trait. You know this because that mode of inheritance is characterized by: • An affected male parent passes the allele to and individuals who have the allele express it and sons and of his daughters. • An affected female parent passes the allele to 588 of her daughters. of his sons of herPlease consider the pedigree below. There are no cases of false paternity. The ABO blood group phenotypes of individuals who marry into the family are a true reflection of their ABO genotypes. image attached I a. Which individual/s definitely has/have Bombay phenotype in the descendants of I-1 and I-2? b. What are the genotypes of individuals I-1 and II-2 at the ABO and H loci?
- marries a woman with non webbed fingers. They hope to have four children. What is the with webbed fingers whose father displayed webbed fingers but whose mother did not amans, webbed fingers is dominant (W-): non webbed fingers is recessive, ww. Aman with webbed fingers whose father displaved webbed fingers but whose mother did hot marries a woman with non webbed fingers. They hope to have four children. What is the probability of three having non webbed fingers and one having webbed fingers? а. 1/2 b. 2/3 С. 3/4 d. 1/8 e. 4The shape of a heliodor is an X-linked trait. Male heliodors inherit two X chromosomes, while the females inherit an X and a Y chromosome. The recessive allele codes for the common bell-shape while the dominant phenotype is a round shape . Hudson is a round male and has offspring with Heidi, a bell-shaped female. They already have one daughter, Hannah, who is shaped like her mother. What percentage of their offspring will be carriers for the bell-shape trait? a.0% b.25% c.50% d.75% e.100%White fruit color in summer squash is dependent on a dominant gene (W) and colored fruit to the recessive gene (w). In the presence of ww a dominant gene D produces yellow color, but when D is not present, the color is green. Upload your solution in the google classroom. Give the: F1_phenotypes_expected_from_crossing_white_fruited_WWDD_with_green_fruited_wwdd_plant F2_phenotypes_expected_from_crossing_the_F1 F2_phenotypic_ratio_expected_from_crossing_the_F1 F2_genotypic_ratio_expected_from_crossing_the_F1 Type_of_epistatis Write all phenotypes in CAPITAL letters SEPARATED BY COMMA. Write all ratio in numerical values without spaces
- Each box represents a potential offspring. Notice that genotypically speaking, they are all the same. Theyare all heterozygous (genotype) which means their phenotype is dark coloration. So, there is 100% chanceof producing a dark eyed, heterozygous offspring. What if that offspring mated with a light eyedindividual? Can you make a Punnett Square for that?Write the Genotypes and Phenotypes of the parents on the left of the square. Complete the square, thenwrite the potential offspring’s genotypes and phenotypes on the right of the square. Parents: Offspring:Genotypes: phenotypes: What are the genotypes of the resulting offspring? What are the phenotypes of the resulting offspring?In individuals affected by cystic fibrosis, salt crystals may appear afterperspiration dries up. In addition, the disease causes respiratory disorderswhich can be both debilitating and lethal. It occurs in individuals homozygousfor recessive gene. If 2 normal parents had a daughter with the symptoms ofthis disease, and a normal son, what is the probability that he might be acarrier of the recessive gene?Express answer in fraction form.The shape of a heliodor is an X-linked trait. Male heliodors inherit two X chromosomes, while the females inherit an X and a Y chromosome. The recessive allele codes for the common bell-shape while the dominant phenotype is a round shape . Hudson is a round male and has offspring with Heidi, a bell-shaped female. They already have one daughter, Hannah, who is shaped like her mother. If their next child is a boy, there is a _____% chance it will be round.