1₁-1A-1₂2=0 (3.64) However, an ideal op amp draws negligible current (A=0) and, therefore, I₁=I₂ and the currents through the two resistors are equal. We can write expressions for I and I₂ by using Ohm's law and dividing the respective voltage drop by the resistance ein (1) - eA R₁ e₁ - eo R₂ The left-side term in Eq. (3.65) is current I, and the right-side term is current I₂. We can rewrite Eq. (3.65) as R₂(ein (1) - eA) = R₁ (e₁-eo) Rearranging Eq. (3.66) with the op-amp input voltage e, on the right-hand side, we obtain R₂ein (1) + R₁eo= (R₁ + R₂)еA or, solving for e R₂ R₁ + R₂ Next, substitute Eq. (3.68) into the amplifier gain equation (3.63) KR₂ R₁ + R₂ ein (1) R₁ www eo = K(eBeA) = + R₂ www 12 K ein (1) + eo R₁ R₁ + R₂ KR₁ R₁ + R₂, eo KR₁ R₁ + R₂ Note that eg = 0 as the positive op-amp input terminal in Fig. 3.13 is directly connected to the ground. Equation (3.69) is rearranged with all output voltage terms on the left-hand side to yield ∙eo KR₂ R₁ + R₂ in (1) (3.65) Figure 3.13 Op-amp circuit for Example 3.6. (3.66) (3.67) (3.68) (3.69) (3.70) The output voltage eo of the op amp shown in Fig. 3.12 is eo = K(eB - eA) (3.63)

2. Figure 1 shows a sensor consists of a core, an armature and a variable air gap. The core with 3.0 cm depth and 10000 relative permeability has 200 coil turns. On the other hand, the armature is a steel plate of thickness 0.2 cm and has similar relative permeability with the core. Assuming the relative permeability of air is unity and the permeability of free space is equal to 4x x 10-7 H.m, calculate the inductance of the sensor for air gaps of 0 mm and 2 mm. Please write the answers in 3 decimal places. 2.0 cm 1.0 cm 6.0 cm 3.0 cm 1.5 cm Figure I

The potentiometer Rx (adjustable resistor) in the given figure is to be designed to adjust current ix from 10 mA to 1 A. Calculate the values of R and Rx by setting the potentiometer to its minimum and maximum values. Assume V = 160 V. (NOTE: Choose a combination, which makes the potentiometer most sensitive.) V R ww Rx ww The value of R and Rx are Ω and kQ, respectively.

5. The purpose of vibration absorber is to reduce vibration at resonance * Choose True False

The equation underneath is do to with resonance, however resonance occurs when the input frequency is equal to the natural frequency what does this equation mean?

Figure 4 shows a simple apparatus for demonstrating resonance in a tube. A tube which is open at the top is filled with water and a vibrating tuning fork of unknown frequency is placed near the top of the tube. The water is allowed to flow through a valve, at the bottom of the tube. Tuning fork p water valve Figure 4 If, the first intensity in the sound is heard when the air column length is p. The next increase is heard when the air column length is y, and the last one is when the air column length is r. Draw the wave pattern happened at p, q and r. Label node and antinode. Calculate the respective frequencies.

vibrations

Don't Use Chat GPT Will Upvote And Give Handwritten Solution Please

Refer to Figure 54–9. If resistor R1 is 470 ohms and resistor R2 is 47 kilohms, what is the gain of the amplifier? Figure 54-9 Inverting amplifier connection.

Solve for v and I