(e) The load in milling factory is having active and reactive power of 100 kW and 59.33kVAr, respectively at voltage supply of 415 V. A capacitor bank system (PFC) withvoltage rating 515 V is to be installed with the target to increase the power factor to95%. The PFC has the step arrangement of 1:1:2:2:3:3 with 5 kVAr for eachcapacitor unit.(i) Analyse the average power factor and the minimum effective reactive power,Os injected into supply system.(ii) Examine the effective reactive power, Qceff to be supplied by capacitor bankand the total unit steps of power factor corrector to be(iii) Estimate the actual average power factor for the system based on the unit steprecommended in Q(e)(ii).(iv) Justify the implication of total unit steps of power factor corrector if 3.3kVArper unit of capacitor is to be used in the factory.

Given Total load power Active power, Pload=100 kW Reactive power, Qload=59.33 kVAr Power factor…

The load in milling factory is having active and reactive power of 100 kW and 59.33 kVAr, respectively at voltage supply of 415 V. A capacitor bank system (PFC) with voltage rating 515 V is to be installed with the target to increase the power factor to 95%. The PFC has the step arrangement of 1:1:2:2:3 :3 with 5 kVAr for each capacitor unit. (1) Analyse the average power factor and the minimum effective reactive power, O, injected into supply system. (ii) Examine the effective reactive power, Qceff to be supplied by capacitor bank and the total unit steps of power factor corrector to be switched 'ON'. (iii) Estimate the actual average power factor for the system based on the unit step recommended in Q(e)(ii). (iv) Justify the implication of total unit steps of power factor corrector if 3.3kVAr per unit of capacitor is to be used in the factory.

The load in milling factory is having active and reactive power of 100 kW and 59.33 kVAr, respectively at voltage supply of 415 V. A capacitor bank system (PFC) with voltage rating 515 V is to be installed with the target to increase the power factor to 95%. The PFC has the step arrangement of 1:1:2:2:3 :3 with 5 kVAr for each capacitor unit. (1) Analyse the average power factor and the minimum effective reactive power, O, injected into supply system. (ii) Examine the effective reactive power, Qceff to be supplied by capacitor bank and the total unit steps of power factor corrector to be switched 'ON'. (iii) Estimate the actual average power factor for the system based on the unit step recommended in Q(e)(ii). (iv) Justify the implication of total unit steps of power factor corrector if 3.3kVAr per unit of capacitor is to be used in the factory.

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter6: Power Flows

Section: Chapter Questions

Problem 6.61P

See similar textbooks

Similar questions

Consider an ideal transformer with N1=3000andN2=1000 turns. Let winding 1 be connected to a source whose voltage is e1(t)=100(1| t |)volts for 1t1ande1(t)=0 for | t |1 second. A2- farad capacitor is connected across winding 2. Sketch e1(t),e2(t),i1(t),andi2(t) versus time t.
6.5% ans ex A so kvA. 2o00/20 V, So He single-phase transformar has impedance drof of8% and resistance drop of 4%. Caleulate. The Requlation of the Thams former at full- Load o8 P.s Legging. also find The Power factor at which Voltage requlation will Be Zero. Sols 0.5 leading. s alculate The % Noltege Requlation af atransformar in w hich the Percantage resistance drof is 1% and Percentage dre is 6% when The Power fador is 0.8 lagging ) > unity aMS 38 % ans 1 % (シ→ 0.8 leading . amS - 2.2%
What is the main direct cause of reactive power in AC system?A. Resistance of transmission linesB. Inductance and capacitance in the loadsC. Ideal transformer connected in the systemD. Power produced by generator
A parallel connection of a RL branch with a C branch is connected across a 100V AC mains. At first R = 10 ohms, L = 20mH and frequency of 1000rad / s, the current measured is 2.2361A at 89.44 leading power factor. A) Determine the initial capacitance. B) However, a fault occurs on the capacitor branch making its capacitance 20% lower and a resistance of 5 ohms is detected. If this faulty circuit is rerun but at a frequency of 500 rad / s, determine the new current that will flow through the circuit
A 250/125 V, five kVA single-phase transformer has a primary resistance of 0.2 ohms and reactance of 0.75 ohms. The secondary resistance is 0.05 ohm and reactance of 0.2 ohms.a) Determine its regulation while supplying full load on 0.8 leading p.f.b) The secondary terminal voltage on full load and 0.8 leading p.f.Ans.: -0.4.88%; 131.1
Example 5: A transformer has 600 primary turns and 150 secondary turns. The primary and secondary resistances are 0.25 2 and 0.01 Q respectively and the corresponding leakage reactances are 1.0 2 and 0.04 Q respectively. Determine: a) The equivalent resistance referred to the primary winding b) The equivalent reactance referred to the primary winding c) The equivalent impedance referred to the primary winding d) The phase angle of the impedance.
1) Calculate the maximum RMS current in p.u. that guarantees the equality of losses between the deformed and non-deformed regime for a power transformer equal to 400 kVA with Pcp = 6% in two cases: a) the transformer feeds a twelve-phase converter Idc=40 A b) the transformer feeds a six-phase converter Idc=40 A.
In a transformer that has 10 times more turns on the secondary side (side 2) than on the primary side (side 1), the magnitude of the voltage/EMF across the windings on the secondary side, E₂ will be... O a.... 10 times lower than the voltage/emf on the primary side, E₁. O b.... the same as the voltage/emf on the primary side. O c.... always zero regardless of the voltage on the primary side, E₁. O d.... 10 times higher than the voltage/emf on the primary side, E₁.
Two 100-kW, single-phase transformers are connected in parallel both on the primary and secondary. One transformer has an ohmic drop of 0.5% at full-load and an inductive drop of 8% at full-load current. The other has an ohmic drop of 0.75% and an inductive drop of 2%. Show how they will share a load of 180 kW at 0.9 p.f.
A 500 MVA synchronous machine has H, = 5.6 MJ/MVA and a 1200 MVA machine has H₂ = 2.0 MJ/MVA. The two machines operate in parallel in a power station. What is the equivalent. H constant for the two, relative to a 100 MVA base?
The efficiency of a transformer at load 0.8 p.f. Lag is -- at load 0.8 p.f. Lead * equal less than more than none of these
The reactance of a generator is given as 0.1 pu based on the generator of 17 KV, 300 MVA. Determine the pu reactance on a base of 17 KV, 250 MVA. New pu reactance is.......