The following eukaryotic DNA sequence is a made up gene. It contains a promoter (green), a coding sequence (yellow to grey), a terminator (grey). Within the coding sequence there are 3 exons (uppercase black) and 2 intron (lower case black). With this information please answer the questions below. 5' ATATTATagctaaatcggtcagAGCATGGCGAGGGC gcgtactcag ACCTAACCTAGA 3' TATAATAtcgatttagccagtcTCGTACCGCTCCCG cgcatgagc TGGATTGGATCT -22 +30 5' tattagcgcatgTGACATCAGAATAAATAAAGCTTTGGGCTTTT 3' ataatcgcgtacACTGTAGTCTTATTTATTTCGAAACCCGAAAA +60 +80

A monocistronic mRNA is defined by… Group of answer choices The presence of a 5’ triphosphate The absence of introns The presence of one coding sequence The absence of a poly(A) tail   Eukaryotic mRNAs are protected on the 5’ end by… Group of answer choices A methylated guanosine A polymer of adenine A triphosphate RNA primer   Eukaryotic mRNAs are typically processed in this order: Group of answer choices Introns spliced out, poly(A) tail added, capped Poly(A) tail added, capped, introns spliced out Capped, poly(A) tail added, introns spliced out Capped, introns spliced out, poly(A) tail added

A mRNA sequence is shown below.  Note that the coding strand of DNA has the same sequence as the mRNA, except that there are U’s in the mRNA where there are T’s in the DNA.  The first triplet of nucleotides AAU (underlined) is in frame for coding, and encodes Asparagine.      45              50              55               60             65              5’—A A C G A A U C G U C G C C A A C U A A G A G  –-3’     Which of the following DNA mutations is almost certain to result in a shorter than normal protein?         at position 56 a change from G to C     an insertion of a G after the G at position 56     inversion of region 56-59 (G C C A)     an delete the C at position 52     None of the above.