The following alkene has stereoisomers. Draw the molecule in the box below which is the other stereoisomer of this alkene (You have two chances until the answer will be given; you have already tried 0 times) H HO-C H.C HC-CH, C=C H Draw only one molecule in each drawing box. Compound #1
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- Draw all the isomers of C5H₁0. Clearly show stereochemistry if stereoisomers are possible. Step 1: Start by drawing all the isomers with double bonds. • Consider constitutional isomers, then stereoisomers. Step 2: Draw all isomers containing a ring. • Consider constitutional isomers, then stereoisomers. Step 2: Next consider isomers containing a ring. The largest ring possible with this molecular formula contains 5 carbons, while the smallest possible ring contains 3 carbons. Draw an isomer containing a 5-carbon ring. Rings More Select Draw / C H Erase Consider a 4-carbon ring of C5H₁0. Draw stereoisomers, if applicable. Select Draw Rings More C H EraseDraw a structural formula for the major organic product of the following reaction:Draw all the isomers of C5H₁0. Clearly show stereochemistry if stereoisomers are possible. Step 1: Start by drawing all the isomers with double bonds. • Consider constitutional isomers, then stereoisomers. Step 2: Draw all isomers containing a ring. • Consider constitutional isomers, then stereoisomers. Consider the constitutional isomers of C5H₁0 that contain a 3-carbon ring. Do not draw stereochemistry. 10 Select C Draw H Rings More Erase
- Draw the structure of the alkene with the molecular formula CH10 that reacts with Br, to give this compound. CH3 Br Br • Use the wedge/hash bond tools to indicate stereochemistry where it exists. • You do not have to explicitly draw H atoms. • In cases where there is more than one answer, just draw one. opyste ot pt pt pt ptN,N-diethyl-m-toluamide (DEET) is the active ingredient in many insect repellent preparations. Following is one of the steps in its synthesis. In the box below draw the structure of the product of this reaction. H3C MgBr 1. CO2 2. H3O+ product • You do not have to consider stereochemistry. • You do not have to explicitly draw H atoms. • Do not include lone pairs in your answer. They will not be considered in the grading. • Draw the Grignard reagent as a covalent magnesium bromide. 90-87 0 + 11 ? n [Here is the chemical structure of 2-bromobutane: Н Η Н Н HHHH C C- C C-H H :Br Η Н .. Decide whether each molecule in the table below is another molecule of 2-bromobutane, a molecule of an isomer of 2-bromobutane, or a molecule of an entirely different compound. molecule CH₂ CH₂-CH₂-CH-Br CH₂ CH₂ -CH₂ Br HI H H H Η H_ H-C- C-C- H-C-H H H relationship to 2-bromobutane (Choose one) (Choose one) Br: a molecule of an isomer of 2-bromobutane ▼