The figure shows two resistors in parallel, with values R1 and R2. The current I, divides between them somehow: 4 +I2 = I0 R1 Io I1 12 R2 (a) Determine the total power dissipated by the circuit as a function of I1, R1, 2, and R2. Your expression should depend on I, and I, but these variables are not independent. Use the constraint that the total current is I, to rewrite your expression for the power as a function of I, and I1. (b) Apply the principle of minimum power dissipation to your expression for the power. That is, minimize the total power with respect to I1, then find the currents I, and Iz that flow through the resistors. Show that this gives the same currents as the standard circuit formula for a "current divider". This illustrates a general variational principle that holds for all direct current networks: The distribution of currents within the network, for given input current I, is always that which gives the least total power dissipation.

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BONUS: Minimal Power
The figure shows two resistors in parallel, with values R¡ and R2. The current Io divides between them somehow:
4+12 = I,
R1
12
R2
(a) Determine the total power dissipated by the circuit as a function of I1, R1, 2, and R2. Your expression should
depend on I, and I,, but these variables are not independent. Use the constraint that the total current is I, to
rewrite your expression for the power as a function of I, and 1.
(b) Apply the principle of minimum power dissipation to your expression for the power. That is, minimize the total
power with respect to I1, then find the currents I, and I, that flow through the resistors. Show that this gives the
same currents as the standard circuit formula for a "current divider".
This illustrates a general variational principle that holds for all direct current networks: The distribution of currents
within the network, for given input current I, is always that which gives the least total power dissipation.
Transcribed Image Text:BONUS: Minimal Power The figure shows two resistors in parallel, with values R¡ and R2. The current Io divides between them somehow: 4+12 = I, R1 12 R2 (a) Determine the total power dissipated by the circuit as a function of I1, R1, 2, and R2. Your expression should depend on I, and I,, but these variables are not independent. Use the constraint that the total current is I, to rewrite your expression for the power as a function of I, and 1. (b) Apply the principle of minimum power dissipation to your expression for the power. That is, minimize the total power with respect to I1, then find the currents I, and I, that flow through the resistors. Show that this gives the same currents as the standard circuit formula for a "current divider". This illustrates a general variational principle that holds for all direct current networks: The distribution of currents within the network, for given input current I, is always that which gives the least total power dissipation.
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