The figure below is a phase diagram for alloys of aluminum and silicon Atomic percentage, com "C 10 60 70 1,300 1414 1,400 1,300 L 1,300 1,100 1000 900 800 700 600.0 600 300 400 300 d R L+B 16 126 a+p Al 30 20 40 50 60 70 Weight percentage, silicon Part A Calculate the weight fraction of the a phase that is proeutectic in a 6 wt%, Si-94 wt% Al alloy at 576°C. Express your answer to three significant figures. 8 i
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- Another of the steel components manufactured by michael's company is steel railway track sections. Thecomponent has a length of 120m (at a temperature of -10°C) and is to be exposed to a temperaturerange of -10°C to 55°C. In order to calculate the gaps which need to be left between the sections michael'scustomer needs to determine the maximum length which each railway track section will expand to andmichael have been asked to carry out the calculation for them. michael have also been instructed to determinethe percentage change in volume and surface area when exposed to the same initial and finaltemperatures. The customer has informed him that the cross sectional profile of the railway track isrectangular and of breadth 14cm and height 32cm. Assume the coefficient of thermal expansion ofsteel is 12x10-6 /°C. Briefly discuss the changes that occur with in the steel as a result of the change intemperature.Three materials X, Y, and Z are available for a certain usage. Any material selected must have a good weldability. Tensile strength, stiffness, stability and fatigue strength are required with fatigue strength considered being the most important and stiffness the least important of these factors. The three materials are rated as follows in these factors. Properties X Y Weldability Excellent Рoor Good Tensile strength G E Fair Stiffness Very Good G G Stability G E G Fatigue strength F G E Which material should be selected? Explain your choice.At a temperature of 60°F, a 0.04-in. gap exists between the ends of the two bars shown. Bar (1) is an aluminum alloy [E = 10,000 ksi; v = 0.32; a = 12.5 x 10-6/°F] bar with a width of 3.0 in. and a thickness of 0.75 in. Bar (2) is a stainless steel [E = 28,000 ksi; v = 0.12; a = 9.6 x 10-6/°F] bar with a width of 2.0 in. and a thickness of 0.75 in. The supports at A and C are rigid. Determine (a) the lowest temperature at which the two bars contact each other. (b) the normal stress in the two bars at a temperature of 250°F. (c) the normal strain in the two bars at 250°F. (d) the change in width of the aluminum bar at a temperature of 250°F. (1) 3.0 in. 32 in. 2.0 in. B ↓ (2) 44 in. 0.04-in. gap Determine the lowest temperature, Tcontact, at which the two bars contact each other.
- At a temperature of 60°F, a 0.04-in. gap exists between the ends of the two bars shown. Bar (1) is an aluminum alloy [E = 10,000 ksi; v = 0.32; α=α=12.5 x 10-6/°F] bar with a width of 2.5 in. and a thickness of 0.75 in. Bar (2) is a stainless steel [E = 28,000 ksi; v = 0.12; α=α=9.6 x 10-6/°F] bar with a width of 1.7 in. and a thickness of 0.75 in. The supports at A and C are rigid. Assume h1=2.5 in., h2=1.7 in., L1=31 in., L2=46 in., and Δ=Δ= 0.04 in. (A) Determine the lowest temperature, Tcontact, at which the two bars contact each other. (B) Find a geometry-of-deformation relationship for the case in which the gap is closed. Express this relationship by entering the sum δ1+δ2, where δ1 is the axial deflection of Bar (1), and δ2 is the axial deflection of Bar (2). δ1+δ2= _____in. (C) Find the force in the Bar (1), F1, and the force in Bar (2), F2, at a temperature of 225oF. By convention, a tension force is positive and a compression force is negative. IN KIPS (D) Find σ1 and σ2,…A tensile force of 5 kN produce an elastic reduction in diameter of 4 x 10-4 mm on a metal alloy specimen that has a diameter of 6 mm. Determine: The modulus of elasticity of the alloy (Unit: GPa) . The Poisson' s ratio of this alloyi need quickly please please please Which of these cast iron would allow the greatest amount of plastic deformation before fracture . Nodular cast iron Grey cast iron White cast iron None of them can be worked. If the diameter of steel specimen stretched by tension load is doubled , then it’s tensile strength will be Halved Remain unaffected Doubled Become four times Temperature is proportional with Percent of elongation Tensile strength Modulus of elasticity All above The tensile strength of a steel specimen that have a 182 HB , equals to 490 MPa 910 MPa 627 MPa Not given…
- At a temperature of 60°F, a 0.02-in. gap exists between the ends of the two bars shown. Bar (1) is an aluminum alloy [E = 10,000 ksi; v = 0.32; α=α=12.5 x 10-6/°F] bar with a width of 2.8 in. and a thickness of 0.85 in. Bar (2) is a stainless steel [E = 28,000 ksi; v = 0.12; α=α=9.6 x 10-6/°F] bar with a width of 1.6 in. and a thickness of 0.85 in. The supports at A and C are rigid. Assume h1=2.8 in., h2=1.6 in., L1=26 in., L2=40 in., and Δ=Δ= 0.02 in. Determine(a) the lowest temperature at which the two bars contact each other.(b) the normal stress in the two bars at a temperature of 225°F.(c) the normal strain in the two bars at 225°F.(d) the change in width of the aluminum bar at a temperature of 225°F.The strength of titanium is 448.16 MPa when the grain size is 17.02 μm and565.4 MPawhen the grain size is0.8μm. What average grain size (in nm) is required to achieve a strength of approximately 839 MPa?c). Interpret the following diagram? The effect of carbon and heat treatment on the properties of plain carbon steels. 160 140 Tensile 120 strength 100 Impact energy | 100 Annealed 80 80 Normalized 60 60 Annealed 40 `Yield strength 20-% Elongation Annealed 20 Normalized- 0.2 0.4 0.6 0.8 1.0 Weight percent carbon Figure-4 Yield and tensile strength (ksi) Normalized % Elongation or impact energy (ft • Ib)
- At a temperature of 60°F, a 0.04-in. gap exists between the ends of the two bars shown. Bar (1) is an aluminum alloy [E = 10,000 ksi; v = 0.32; a = 12.7 x 10-6/°F] bar with a width of 3 in. and a thickness of 0.75 in. Bar (2) is a stainless steel [E = 28,000 ksi; v = 0.12; a = 8.6 x 10-6/°F] bar with a width of 2 in. and a thickness of 0.75 in. The supports at A and C are rigid. Determine the lowest temperature at which the two bars contact each other. (1) 3 in. 32 in. 90.2°F O 69.9°F 139.2°F 103.5°F O 111.0°F B ↑ 2 in. ↓ 44 in. -0.04-in. gapAt a temperature of 60°F, a 0.04 in. gap exists between the ends of the two bars shown in the figure. Bar (1) is an aluminum alloy [E=10000 ksi; v=0.32; a= 12.5 x10^-6/,°F] bar with a width of 3 in. and a thickness of 0.75 in. Bar (2) is a stainless steel [E= 28000 ksi; v=0.12; a=9.6x10^-6/°F] bar with a width of 2 in and a thickness of 0.75 in. The supports at A and C are rigid. Determine the normal stress in bar (1) at a temperature of 380°F. Answer in ksiCompare the difference in hardenability of plain carbon steels given below. Hardenability is the strengthening of steels by the process of quenching + tempering. Chemical compositions ( wt % ) C Mn P S Fe Steel 1 0.2 0.45 0.04 0.05 99.26 Steel 2 0.4 0.75 0.04 0.05 98.76 Steel 3 0.6 0.75 0.04 0.05 98.56