Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN: 9780133594140
Author: James Kurose, Keith Ross
Publisher: PEARSON
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- In XOR Cipher, encoding is done by an XOR operation on two given strings. If the strings are of different lengths then the output should be the length of the shorter string. Cut the length of the longer string to the same size as the smaller string before XOR operation. Given two strings of msg1 and msg2, return the encoded message. Examples xor_cipher ("11", "22") "33" # 11 XOR 22 = 33 RUBY xor_cipher ("1020304", "403201") xor_cipher ("c611d9bdd9de38b9eb", "23a0745505d4d25494") "e5b1ade8dc0aeaed7f" "501231"arrow_forwardIn the case of Public Key Authority It is necessary to make a request for B's public key, and the Public Key Authority must prepare a message (E(PRauth[PUB] || Request || Time1]) before sending it to A. What key A should use to decipher the message is up for debate.arrow_forwardPublic Key Authority is one such instance. The Public Key Authority must prepare a request for B's public key before delivering a message to A (E(PRauth[PUB || Request || Time 1]). It is debated if the letter A should be used to decipher the message.arrow_forward
- Plz don't use chat gptarrow_forwardAlice sets up an RSA public/private key, but instead of using two primes, she chooses three primes p, q, and r and she uses n=pqr as her RSA-style modulus. She chooses an encryption exponent e and calculates a decryption exponent d. Encryption and Decryption are defined: C ≡ me mod n and m ≡ Cd mod n where C is the ciphertext corresponding to the message m. Decryption: de ≡ 1 mod φ(n) | Let p = 5, q = 7, r = 3, e = 11, and the decryption exponent d = -13. n = 105 & φ(n) = 48 Q: Alice upgrades to three primes that are each 200 digits long. How many digits does n have?arrow_forwardDesign a cryptographic solution for implementing the dinning cryptographers protocol. You should consider the following: The secret messages shared between any two agents in the protocol are communicated over public channels only. The announcements made by each agent must be traceable in a trustworthy way to that agent. Your solution should be a new protocol that addresses the above two requirements.arrow_forward
- Computer Science Assume we use transposition cipher to encrypt the data, and the original message is stored in a 8 by 5 matrix (8 rows and 5 columns). If the ciphertext is shown below, what is the original plaintext?WMHPSCATEEEUCELELTCTIASLOTMRNCAarrow_forwardSuppose your RSA public key is PK: {n, e} = {13861, 37}. Your friend sends you a ciphertext C = 9908. But unfortunately you have forgotten your private key, now you have to crack it yourself.a) Write down a possible condition of factors p and q.p= q=b) What is your private key SK: {d}?d=c) What is the plaintext of your friend’s message?The plaintext M =d) Suppose the plaintext M is a 12-digit number consisting of a prefix “19” and 1234567890. What is the corresponding ciphertext? Since M is greater than n, you only need to encrypt four digits at a time. Ignore redundant zeros. e.g., 0001 = 1. The result should contain three integers.The ciphertext C0 =arrow_forwardA ciphertext has been generated with an affine cipher. The most frequent letter of the ciphertext is “F”, and the second most frequent letter of the ciphertext is “C”. Break this code by figuring out the key numbers. Hint: Based on the letter frequency, E is the most frequent letter and T is the second most frequent letter. Therefore, F should be the ciphertext of E and C should be the ciphertext of T.arrow_forward
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