The equilibrium constant, Kp, for the following reaction is 1.57 at 600 K: CO(g) + Cl2(g) coCI,(g) Calculate the equilibrium partial pressures of all species when CO and Cl2, each at an intitial partial pressure of 1.88 atm, are introduced into an evacuated vessel at 600 K. Рсо atm Pcl2 atm Pcoclz atm

A chemical engineer is studying the following reaction: N₂(g) + 3H₂(g) → 2 NH3(g) At the temperature the engineer picks, the equilibrium constant K for this reaction is 0.00014. The engineer charges ("fills") three reaction vessels with nitrogen and hydrogen, and lets the reaction begin. He then measures the composition of the mixture inside each vessel from time to time. His first set of measurements are shown in the table below. Predict the changes in the compositions the engineer should expect next time he measures the compositions. reaction vessel A B C compound N₂ H₂ NH3 N₂ H₂ NH₂ N₂ H₂ NH₂ pressure 32.70 atm 49.38 atm 23.45 atm 33.09 atm 50.55 atm 22.67 atm 33.10 atm 50.59 atm 22.64 atm expected change in pressure ↑ increase ↑ increase ↑ increase ↑ increase ↑ increase O ↑ increase ↑ increase ↑ increase ↑ increase decrease ↓ decrease ↓ decrease ↓ decrease ↓ decrease decrease ↓ decrease decrease decrease (no change) (no change) (no change) (no change) (no change) O (no change) (no…

The equilibrium constant, Kp, for the following reaction is 5.40 at 346 K:COBr2(g)  CO(g) + Br2(g)Calculate the equilibrium partial pressures of all species when COBr2(g) is introduced into an evacuated flask at a pressure of 0.767 atm at 346 K. PCOBr2 =  atm PCO =  atm PBr2 =  atm

At 1560 oC the equilibrium constant for the reaction: 2 IBr(g)  I2(g) + Br2(g) is KP = 0.846. If the initial pressure of IBr is 0.00674 atm, what are the equilibrium partial pressures of IBr, I2, and Br2?p(IBr) =  p(I2) =  p(Br2) =

A student ran the following reaction in the laboratory at 303 K:2NO(g) + Br2(g) 2NOBr(g)When she introduced NO(g) and Br2(g) into a 1.00 L evacuated container, so that the initial partial pressure of NO was 1.15 atm and the initial partial pressure of Br2 was 0.408 atm, she found that the equilibrium partial pressure of Br2 was 0.138 atm.Calculate the equilibrium constant, Kp, she obtained for this reaction. Kp =

The equilibrium constant, Kc, for the following reaction is 55.6 at 698 K.H2 (g) + I2 (g) 2 HI (g)Calculate the equilibrium concentrations of reactants and product when 0.228 moles of H2 and 0.228 moles of I2 are introduced into a 1.00 L vessel at 698 K. [ H2 ] = M [ I2 ] = M [ HI ] = M

The equilibrium constant (Kc ) for the reaction: PCl3 + Cl2 <=> PCl5 equals 51 at 235°C. If 0.648 mol  of phosphorus trichloride and 0.748 mol chlorine (Cl2) are added to a 9.00 L reaction vessel, what is the amount of moles of Cl2 at equilibrium  in the mixture at 235°C?

The equilibrium constant Kp for the reaction PC15(g) = PC13(g) + Cl₂(g) is 1.05 at 250°C. The reaction starts with a mixture of PC15, PC13, and Cl₂ at pressures 0.177 atm, 0.233 atm, and 0.161 atm, respectively, at 250°C. When the mixture comes to equilibrium at that temperature, which pressure(s) will have decreased? Cl₂ PC13 PC15

A chemical engineer is studying the following reaction: H2(9)+Cl2(g) → 2 HCl(g) At the temperature the engineer picks, the equilibrium constant K, for this reaction is 1.1. The engineer charges ("fills") three reaction vessels with hydrogen and chlorine, and lets the reaction begin. He then measures the inside each vessel from time to time. His first set of measurements are shown in the table below. Predict the changes in the compositions the engineer should expect next time he measures the compositions. reaction vessel compound pressure expected change in pressure H, 2.75 atm t increase I decrease (no change) Cl, 4.00 atm t increase O I decrease O (no change) A HCI 2.10 atm O f increase OI decrease O (no change) H, 2.78 atm t increase I decrease O (no change) Cl, 4.03 atm t increase I decrease (no change) 2.06 atm t increase I decrease (no change) HCl H2 3.22 atm O f increase I decrease (no change) t increase I decrease (no change) Cl, 4.98 atm OI decrease O (no change) H CI 4.26 atm…

Write the expression for the equilibrium constant Kp for the following reaction.Enclose pressures in parentheses and do NOT write the chemical formula as a subscript. For example, enter (PNH3)2 as (P NH3)2 . If either the numerator or denominator is 1, please enter 1   2 Co3O4(s)   ↔   6 CoO(s) + O2(g)