The equilibrium constant, K,, for the following reaction is 0.636 at 600 K: CoC,(g) CO(g) + Cl(g) Calculate the equilibrium partial pressures of all species when COC1,(g) is introduced into an evacuated flask at a pressure of 1.33 atm at 600 K. PcocI, = atm Рсо atm atm

The partial pressures at equilibrium in a 4.530L flask are: HI(g) at 0.533atm and p H2(g)=p I2(g)=0.0533atm. If additional HI(g) is added to the flask so it's partial pressure is increased to 0.750atm, calculate the partial pressures of HI,H2 and I2 once equilibrium is re-established.

A student ran the following reaction in the laboratory at 295 K:2NO(g) + Br2(g) 2NOBr(g)When she introduced NO(g) and Br2(g) into a 1.00 L evacuated container, so that the initial partial pressure of NO was 1.26 atm and the initial partial pressure of Br2 was 0.587 atm, she found that the equilibrium partial pressure of NOBr was 0.701 atm.Calculate the equilibrium constant, Kp, she obtained for this reaction.Kp =

CO2 and H, are allowed to react until an equilibrium is established as follows: CO2 (g) + H, (g)H,0 (g) + CO (g) What will be the effect on the equilibriumn of removing CO from the equilibrium mixture?

The formation of nitrogen monoxide from its elements has an equilibrium which favors reactants: N2 (g) + 02 (g) 2 NO (g) K, = 0.0290 at 2400°C If the initial partíal pressures of both reactant gases are 0.717 atm, what will be the equilibrium partial pressure of nitrogen monoxide? (A certain simplification is valid in solving this problem). 0.112 atm (A) (B) 0.0290 atm (C) 0.688 atm (D) 0.0563 atm (E) 0.0611 atm

When 0.200 mol of CaCO,(s) and 0.300 mol of CaO(s) are placed in an evacuated, sealed 10.0-L container and heated to 385 K, PCO, = 0.220 atm after equilibrium is established. 2 CACO,(s) = CaO(s) + CO,(g) Additional CO,(g) is pumped into the container to raise the pressure to 0.470 atm. After equilibrium is re-established, what is the total mass (in g) of CaCO, in the container?

A student ran the following reaction in the laboratory at 588 K: CO(g) + Cl₂(g) —COCI₂(g) When she introduced CO(g) and Cl₂(g) into a 1.00 L evacuated container, so that the initial partial pressure of CO was 1.74 atm and the initial partial pressure of Cl2 was 0.951 atm, she found that the equilibrium partial pressure of COCI₂ was 0.685 atm. Calculate the equilibrium constant, Kp, she obtained for this reaction. Кр =

Type the word True or False in the provided space for the following. Consider the following system at equilibrium where Kc = 9.52x10-2 and AH° = 18.8 kJ/mol at 350 K. CH4 (g) + CCl4 (g) → 2 CH₂Cl₂ (g) The production of CH₂Cl2 (g) is favored by: decreasing the temperature. increasing the pressure. increasing the volume. removing CH₂Cl2. removing CCl4. I. II. III.____ IV. V.