The electric field magnitude on the surface of an irregularly shaped conductor varies from 56.0 kN/C to 28.0 kN/C. Can you evaluate the electric potential on the conductor? If so, find its value. If not, explain why not.

D only please

Consider two widely separated conducting spheres, 1 and 2, the second having six times the diameter of the first. The smaller sphere initially has a positive charge q = 1.00×10-6 C, and the larger one is initially uncharged. You now connect the spheres with a long thin wire. a) How are the final potentials V1 and V2 of the spheres related? Find the final charges q1 b) and q2. c)What is the ratio of the final surface charge density of sphere 1 to that of sphere 2?

Problem 2: A point mass of charge q > 0 moves at 35° to a uniform electric field E for a total distance d. Part (a) Select a diagram that follows from the problem description. Part (b) The charge q travels from point y, to point y2, where the total traveled distance is d. Find the potential difference that the charge traverses. When you enter your answer you can assume that y, = 0 V2 - V = cos(a) cos(o) cos(e) 7 8 9 HOME sin(a) sin(@) sin(e) 5 6 3 d E - END h Vol BACKSPACE DEL CLEAR

Find an expression for Electric Potential differences formed by a semicircle charged rod with a total charge of 50 micro.C at the center of a semicircle with a radius of R= 30.0 cm.

A plastic disk of radius R = 72.2 cm is charged on one side with a uniform surface charge density 7.67 fC/m², and then three quadrants of the disk are removed. The remaining quadrant is shown in the figure. With V = 0 at infinity, what is the potential in volts due to the remaining quadrant at point P, which is on the central axis of the original disk at distance D = 0.429 cm from the original center? D

A conducting sphere of radius 5.0 cm is given a net amount of charge of 3.0 x109 C. Note: 109 C = 1 nC (1 nanocoulomb). What is the potential at a distance of 0.55 m from the center of the sphere? Assume that the electric potential at a very large distance from the sphere equals zero. V = V

Two parallel plates have equal and opposite charges. When the space between the plates is evacuated, the electric field is E= 3.30×105 V/m. When the space is filled with dielectric, the electric field is E= 2.50×105 V/m. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Energy density, both before and after the. What is the charge density on each surface of the dielectric? Express your answer in coulombs per meter squared. να ΑΣΦ ? |X| X•10" |oi| = C/m²

Over a certain region of space, the electric potential is V = 7x - 2x2y + 2yz2. Find the expression for the x component of the electric field over this region. (Use the following as necessary: x, y, and z.) Ex =     Find the expression for the y component of the electric field over this region. Ey =     Find the expression for the z component of the electric field over this region. Ez =     What is the magnitude of the field at the point P, which has coordinates (7, 0, -7) m? N/C

Figure 1 shows two sets of equi-potential surfaces due to charge q₁ and charge 92. An external agent moves an electron (e = 1.6 × 10-¹⁹ C) from position a to position b. 50 V91 25 V 110 V 110 V 92 50 V Figure 1: Two sets of equi-potential surfaces a) State whether the charges q₁ and q2 are positive or negative. Justify your answer.