College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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Find an expression for Electric Potential differences formed by a semicircle charged rod with a total charge of 50 micro.C at the center of a semicircle with a radius of R= 30.0 cm.
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- Problem 12: A uniformly charged rod of length L = 1.4 m lies along the x-axis with its right end at the origin. The rod has a total charge of Q = 8.2 μC. A point P is located on the x-axis a distance a = 1.8 m to the right of the origin. Part (a) Consider a thin slice of the rod of thickness dx located a distance x away from the origin. What is the direction of the electric field at point P due to the charge on this thin slice of the rod? Part (b) Write an equation for the electric field dE at point P due to the thin slide of the rod dx. Give your answers in terms of the variables Q, L, x, a, dx, and the Coulomb constant, k. Notice that the coordinate x will be less than zero over the length of the rod. Part (c) Integrate the electric field contributions from each slice over the length of the rod to write an equation for the net electric field E at point P. Part (d) Calculate the magnitude of the electric field E in kilonewtons per coulomb (kN/C) at point P due to the charged…arrow_forwardA small plastic ball of mass 8.19 × 10³ kg and charge +0.116 μC is suspended from an insulating thread and hangs between the plates of a capacitor (see the drawing). The ball is in equilibrium, with the thread making an angle of 30.0° with respect to the vertical. The area of each plate is 0.01280 m². What is the magnitude of the charge on each plate? 30.0⁰ IN + ++ + ▬▬▬▬▬▬▬▬▬▬▬▬▬▬arrow_forwardA charge Q= 3nC is uniformly distributed over a ring of radius a = 6 cm. An electron is released from rest at point C, which is 8 cm away from the center O of the ring. Find the speed (in 10° m/s) of the electron as it passes through point O. Hint: me = 9.11x10-3 kg.arrow_forward
- A solid core carrying excess charge, Q = 46.4 μC, is located at the center of concentric spherical shells. The two spheres are joined by a hollow plastic tube that starts at the radius of the small sphere, r = 17.5 cm, and ends at the radius of the large one, R = 38.5 cm. When a charge, q = 6.9 μC, is placed at the inner end of the tube and released from rest, it accelerates straight through the tube and out the other end as shown. - kog ( ² = − 1 / 2 ) kQq R (a) How much did the electric potential energy change as the particle moved from one end of the tube to the other? Write your answer symbolically, in terms of Q, q, r, R and constants (as needed), then calculate its numeric value. AUE= = 8.97 X R x J (b) How much electric potential energy will be left when the little charge is 73.5 cm from the core? UE = 7.48 J 9arrow_forwardcan you please ans (k) & ( l)?arrow_forwardSuppose a speck of dust in an electrostatic precipitator has1.0000×1012 protons in it and has a net charge of –5.00 nC (a very large charge for a small speck). How many electrons does it have?arrow_forward
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