The elastic portion of the stress-strain diagram for an aluminum alloy is shown in the figure. The specimen from which it was obtained has an original diameter of 12.7 mm and a gage length of 50.8 mm. If a load of P=60 kN is applied to the specimen, determine its new diameter and length. Take v = 0.35. o (MPa) 490 e (mm/mm) 0.007

The elastic portion of the stress-strain diagram for an aluminum alloy is shown in the figure. The specimen from which it was obtained has an original diameter of 12.7 mm and a gage length of 50.8 mm. If a load of P=60 kN is applied to the specimen, determine its new diameter and length. Take v = 0.35. o (MPa) 490 e (mm/mm) 0.007

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

3. The elastic portion of the stress-strain diagram for a steel alloy is shown in the figure below. The specimen from which it was obtained had an original diameter of 13 mm and a gauge length of 50 mm. If a load of P = 20 kN is applied to the specimen, determine its diameter and gauge length. Take v = 0.4 σ (MPa) 400 0.002 e(mm/mm)
*84 The stress-strain diagram for a metal alloy having an original diameter of 12 mm and a gauge length of 50 mm is given in the figure. Determine approximately the modulus of elasticity for the material, the load on the specimen that causes yielding, and the ultimate load the specimen will support. a (MPa) 600 500 400 300 200 100 -e(mm/mm) o 004 008 a12 0.16 0.20 024 0.28 O 0005 0.001 0.0015 0002 0.0025 0.003 0.0035
The elastic portion of the tension stress–strain diagram for an aluminum alloy is shown in the figure. The specimen used for the test has a gage length of 2 in. and a diameter of 0.5 in. If the applied load is 10 kip, determine the new diameter of the specimen. The shear modulus is Gal = 3.811032 ksi.
R8-1. The elastic portion of the tension stress-strain diagram for an aluminum alloy is shown in the figure. The specimen used for the test has a gauge length of 50 mm and a diameter of 12.5 mm. When the applied load is 40 kN, the new diameter of the specimen is 12.4800 mm. Compute the shear modulus G, for the aluminum. a (MPa) 350 (mm/mm) 0.00480
The stress-strain diagram for a steel alloy having an original diameter of 0.5 in. and a gage length of 2 in. is given in the figure. Determine approximately the modulus of elasticity for the material, the load on the specimen that causes yielding, and the ultimate load the specimen will support. o (ksi) 80 70 60 50 40 30 20 10 e (in./in.) 0 0.04 0.08 0.12 0.16 0.20 0.24 0.28 0 .0.0005 0.0010.0015 0.002 0.0025 0.0030.0035
The elastic portion of the stress-strain diagram for an aluminum alloy is shown in the figure below (Figure 1). The specimen from which it was obtained has an original diameter of 12.7 mm and a gage length of 50.5 mm. Take v=0.35 Figure σ (MPa) 490 0.007 € (mm/mm) Part A If a load of P = 40 kN is applied to the specimen, determine its new diameter. Express your answer to four significant figures and include appropriate units. d= Submit Part B L= O Value Submit μA Request Answer Determine its length. Express your answer to four significant figures and include appropriate units. Provide Feedback Value Units Request Answer ? Units ?
The elastic portion of the stress–strain diagram for an aluminum alloy is shown in the figure. The specimen from which it was obtained has an original diameter of 12.7 mm and a gage length of 50.8 mm. If a load of P = 60 kN is applied to the specimen, determine its new diameter and length. Taken = 0.35.
σ (MPa) 490 0.007 -e (mm/mm) A specimen has the stress-strain diagram shown. The specimen has an original diameter of 12.4 mm, and its modulus of rigidity is 27.4 GPa. Determine the specimen's diameter when the longitudinal stress is 325 MPa.
2) The elastic portion of the tension stress-strain diagram for an aluminum alloy is shown in the figure. The specimen used for the test has a gauge length of 50 mm and a diameter of 12.5 mm. When the applied load is 45 KN, the new diameter of the specimen is 12.48375 mm. Compute the shear modulus (Gal) for the aluminum. σ (MPa) 500 71 0.00614 € (mm/mm)
The stress-strain diagram for an aluminum alloy specimen having an original diameter of 0.5 in. and a gauge length of 2 in. is given in the figure. If the specimen is loaded until it is stressed to 60 ksi, determine the approximate amount of elastic recovery and the increase in the gage length after it is unloaded.
The elastic region of the tension stress-strain diagram for an aluminum alloy is shown in (Figure 1). The specimen used for the test has a gage length of 2 in. and a diameter of 0.5 in. The shear modulus is Gal = 3.8 (10³) ksi. Figure σ (ksi) 70 VI 0.00614 1 of 1 € (in./in.) Part A If the applied load is 15 kip, determine the new diameter of the specimen. Express your answer in inches to four significant figures. IVE ΑΣΦ ↓↑ vec d' = Submit Provide Feedback Request Answer ? in.
Nylon strips are fused to glass plates. When moderately heated the nylon will become soft while the glass stays approximately rigid. Determine the average shear strain in the nylon due to the load P when the assembly deforms as indicated. 2 mm P. 3 mm 5 mm 3 mm 5 mm 3 mm