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The code below has a Basic Computer assembly subroutine named XM2NY that computes X- 2NY and returns the results in the AC. In the code shown, the main program calls the subroutine twice to compute: 1-2 (56-24*3). Hint: Multiplication by 2 can be done by a logic shift. Complete the missing code below, and then answer the following questions after it: ORG 200 BSA XM2NY Y1, DEC N1, DEC -4 X1, DEC 56 STA Y2 BSA XM2NY Y2, DEC N2, DEC -3 X2, DEC HLT XM2NY, НЕХ 0 LDA XM2NY I ISZ XM2NY СМА LOP, CLE ISZ XM2NY I BUN LOP ISZ XM2NY XM2NY I ISZ XM2NY XM2NY I END • The value of the symbol LOP in hexadecimal is • If an interrupt occurs during the execution of STA Y2 then the content of the memory at address 0 in hexadecimal is

The code below has a Basic Computer assembly subroutine named XM2NY that computes X- 2NY and returns the results in the AC. In the code shown, the main program calls the subroutine twice to compute: 1-2 (56-24*3). Hint: Multiplication by 2 can be done by a logic shift. Complete the missing code below, and then answer the following questions after it: ORG 200 BSA XM2NY Y1, DEC N1, DEC -4 X1, DEC 56 STA Y2 BSA XM2NY Y2, DEC N2, DEC -3 X2, DEC HLT XM2NY, НЕХ 0 LDA XM2NY I ISZ XM2NY СМА LOP, CLE ISZ XM2NY I BUN LOP ISZ XM2NY XM2NY I ISZ XM2NY XM2NY I END • The value of the symbol LOP in hexadecimal is • If an interrupt occurs during the execution of STA Y2 then the content of the memory at address 0 in hexadecimal is

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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6:39 موسي نتشة Just now The code below has a Basic Computer assembly subroutine named XM2NY that computes X- 2NY and returns the results in the AC. In the code shown, the main program calls the subroutine twice to compute: 1-2 (56-24*3). Hint: Multiplication by 2 can be done by a logic shift. Complete the missing code below, and then answer the following questions after it: ORG 200 BSA XM2NY Y1, DEC 3 N1, DEC -4 X1, DEC 56 STA Y2 BSA XM2NY Y2, DEC N2, DEC -3 X2, DEC HLT XM2NY, HEX O LDA ΧM2NY Ι ISZ XM2NY СМА LOP, CLE ISZ XM2NY I BUN LOP ISZ ΧM2NY XM2NY I ISZ XM2NY XM2NY I END • The value of the symbol LOP in hexadecimal is • If an interrupt occurs during the execution of STA Y2 then the content of the memory at address 0 in hexadecimal is
Transcribed Image Text:6:39 موسي نتشة Just now The code below has a Basic Computer assembly subroutine named XM2NY that computes X- 2NY and returns the results in the AC. In the code shown, the main program calls the subroutine twice to compute: 1-2 (56-24*3). Hint: Multiplication by 2 can be done by a logic shift. Complete the missing code below, and then answer the following questions after it: ORG 200 BSA XM2NY Y1, DEC 3 N1, DEC -4 X1, DEC 56 STA Y2 BSA XM2NY Y2, DEC N2, DEC -3 X2, DEC HLT XM2NY, HEX O LDA ΧM2NY Ι ISZ XM2NY СМА LOP, CLE ISZ XM2NY I BUN LOP ISZ ΧM2NY XM2NY I ISZ XM2NY XM2NY I END • The value of the symbol LOP in hexadecimal is • If an interrupt occurs during the execution of STA Y2 then the content of the memory at address 0 in hexadecimal is
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