AC analysis:The signal source is ??(?)=5sin?? mV. The transistor parameters are β = 120 and VA = ∞. (a) (i) Design the circuit such that ??? = 0.25 mA and ???? = 3 V. (ii) Find the small-signal voltage gain ??=????⁄. (iii) Find ??(?). (b) Repeat part (a) for RS = 0. The signal source is vs(t) = 5 sin wt mV. The transistor parameters are ß = 120 and V₁ = ∞. (a) (i) Designthe circuit such that Icq = 0.25 mA and VCEQ = 3 V. (ii) Find the small-signal voltage gain Av = /vs. (iii)Find vo(t). (b) Repeat part (a) for RS = 0.Vs+Rs = 2.5 kwwwFigure P6.18V+ = +5 VwwRCREV-=-5 VCcHH1₁wwCER₁ = 5kQ2

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Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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AC analysis:

The signal source is ??(?)=5sin?? mV. The transistor parameters are β = 120 and VA = ∞. (a) (i) Design the circuit such that ??? = 0.25 mA and ???? = 3 V. (ii) Find the small-signal voltage gain ??=????⁄. (iii) Find ??(?). (b) Repeat part (a) for RS = 0.

The signal source is vs(t) = 5 sin wt mV. The transistor parameters are ß = 120 and V₁ = ∞. (a) (i) Design
the circuit such that Icq = 0.25 mA and VCEQ = 3 V. (ii) Find the small-signal voltage gain Av = /vs. (iii)
Find vo(t). (b) Repeat part (a) for RS = 0.
Vs
+
Rs = 2.5 k
www
Figure P6.18
V+ = +5 V
ww
RC
RE
V-=-5 V
Cc
HH1₁
ww
CE
R₁ = 5kQ2

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