The circuit shown in the figure is at steady state before the switch opens at t = 0. The switch remains open for 0.5 second and then closes. Determine v(t) for t > 0* and assume L = 40H. %3D t = 0.5 s 40 2 t = 0 s 24 V 10 2 L. v(t) 40 Q.

Switch S in in the figure is closed at time t = 0, to begin charging an initially uncharged capacitor of capacitance C = 15.1 µF through a resistor of resistance R = 22.4 2. At what time is the potential across the capacitor equal to that across the resistor? +0 www R

For the R-C circuit in Figure, composed of standard values: I would like to check my answer Determine the time constant of the circuit when the switch is throwninto position 1. I got 0.2s Find the mathematical expression for the voltage across the capacitorand the current after the switch is thrown into position 1. I got Vc = 8V(1-e-t/0.2s) ic = 4e-t/0.2smA And for the Determine the magnitude of the voltage vC and the current iC the instantthe switch is thrown into position 2 at t = 1 s. I got Vc = 7.95V and Ic = 0.02695mA Can you check if its correct

The Capacitor value is 0.08 F.