The beam is designed to carry a fluctuating stress from a load of 1,200-lb. The beam is made of Cold-Drawn AISI 1040 steel (wrought steel). Using the Goodman Method for Fatigue of Ductile materials, determine the design factor, N. 10 in 1200 lb 10 in 2-in dia
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- Three round, copper alloy bars having the same length L but different shapes are shown, in the figure. The first bar has a diameter d over its entire length, the second has a diameter d over one-fifth of its length, and the third has a diameter d over one-fifteenth of its length. Elsewhere, the second and third bars have a diameter Id. All three bars are subjected to the same axial load P. Use the following numerical data: P = 1400 kN, L = 5m,d= 80 mm, E= 110 GPa. and v = 0.33. (a) Find the change in length of each bar. (b) Find the change in volume of each bar.Find the equivalent stresses at Points 1 and 2 of the element with given geometry and loading conditions according to the Maximum shear stress hypothesis and the Maximum strain energy hypothesis. Shaft diameter: 20 mm, Shaft Length 120 mm, F1 = 750N, F2 = 3000N, Mb = 2400 N.mm. Steel if St37 and Safety coefficient is 2 If taken, will this stick work safely under these operating conditions? (Yield of given steel Strength 225 Mpa, Tensile strength 370 Mpa)4. A beam has fluctuating bending moment and is not rotating. The bending moment has a maximum of 1kNm and a minimum of 100kNm. The beam is made of AISI1020CD steel with a square cross section. There are no stress concentrations. a. Determine the fully corrected endurance limit as a function of the cross section (cross section unknown) b. Determine the required size for a factor of safety of 2 using the Gerber Fatigue Failure Theory
- 21 A simply supported beam of circular cross- section made up of hot rolled steel is subjected to a fluctuating load that varies from -F to +3F. Determine the minimum ultimate strength of the beam material which can withstand the fluctuating loads. The variable forces on the beam induce corresponding fluctuating stresses between + 82 N/mm2 to -36 N/mm2. Assume the following values: Yield strength = 0.55 ultimate strength, endurance stress = 0.45 ultimate strength. Take a factor of safety = 2. Use Soderberg relation in your design, i) Calculate the mean stress in N/mm2 and variable stress in N/mm² ii) Calculate the Ultimate Strength in N/mm2 iii) Calculate the endurance strength in N/mm2A cantilever beam of circular cross-section is made of alloy steel is subjected to a fluctuating load that varies from -F to 2F. Determine the minimum ultimate strength of the beam material which can withstand the fluctuating loads. The variable forces on the beam induce corresponding fluctuating stresses between + 48 N/mm2 to -24 N/mm?. Assume the following values. Yield strength = 0.55 ultimate strength, endurance stress = 0.45 ultimate strength. Take a factor of safety = 2. Use Soderberg relation in your design i) Calculate mean and alternating stress ii) Calculate endurance strength **Note: Please upload your handwritten working/solution to the link provided. Mean Stress in N/mm^2 ... Variable Stress in N/mm^2 ... Endurance Strength in N/mm^2 .. Ultimate Strength in N/mm^2..12. A cylindrical steel bar (1045 steel) is subjected to repeated tension-compression stress cycling along its axis. If the load amplitude is 20 kN, calculate the minimum allowable bar radius to avoid fatigue failure. Use a safety factor of 2.5 and use the below figure for the fatigue limit stress. Round answer to two significant figures. Stress amplitude, S (MPa) 500 400 300 200 100 10³ 104 105 1045 steel 2014-T6 aluminum alloy Red brass 10 107 10" Cycles to failure, N 10 T 70 60 50 40 30 20 10 0 1010 Stress amplitude (10 psi)
- A cantilever beam as shown in Fig. is subjected to a load which varies from - F to 4F. Determine the maximum load that this member can withstand for indefinite life using a factor of safety as 2. The theoretical stress concentration may be assumed as 1.42 and the notch sensitivity is 0.8. Assume surface factor as 0.85 and the size factor as 0.8. The beam material has an ultimate tensile strength of 500 MPa, yield strength of 350 MPa.A simply supported beam of circular cross-section made up of hot rolled steel is subjected to a fluctuating load that varies from -F to +3F. Determine the minimum ultimate strength of the beam material which can withstand the fluctuating loads. The variable forces on the beam induce corresponding fluctuating stresses between + 82 N/mm2 to –42 N/mm2. Assume the following values: Yield strength = 0.55 ultimate strength, endurance stress = 0.45 ultimate strength. Take a factor of safety = 2. Use Soderberg relation in your design, i) Calculate the mean stress in N/mm2 and variable stress in N/mm2 ii) Calculate the Ultimate Strength in N/mm2 iii) Calculate the endurance strength in N/mm2The beam shown: Made from carbon steel 1030-hot rolled Notch sensitivity factor 0.8 Reliability is 50%, Operating temperature 120 C" Design safety factor 1.5 Determine the diameter (d) of the beam such that it not fail for a life of 100000 cycles under the load shown. All dimensions in (mm) Make any reasonable assumptions 170 150 1 A P + 1000 N 0.25d d. 1.5d
- A steel rod is subjected to a reversed axial load of 180 kN. Find the diameter of the rod for a factor of safety of 2. Neglect column action. The material has an ultimate tensile strength of 1070 MPa and yield strength of 910 MPa. The endurance limit in reversed bending may be assumed to be one-half of the ultimate tensile strength. Other correction factors may be taken as follows: For axial loading (Ka) = 0.7; For machined surface (Ksur) = 0.8 ; For size (Ksz) = 0.85 ; For stress concentration(Kf)= 1.0.3.A simply supported beam of circular cross-section made up of hot rolled steel is subjected to a fluctuating load that varies from -F to +3F. Determine the minimum ultimate strength of the beam material which can withstand the fluctuating loads. The variable forces on the beam induce corresponding fluctuating stresses between + 88 N/mm2 to –38 N/mm2. Assume the following values: Yield strength = 0.55 ultimate strength, endurance stress = 0.45 ultimate strength. Take a factor of safety = 2. Use Soderberg relation in your design, i) Calculate the mean stress in N/mm2 and variable stress in N/mm2 ( ii) Calculate the Ultimate Strength in N/mm2 i) Calculate the endurance strength in N/mm2Fill in the blanks: Find the size of wire in mm if the maximum design stress is 425 000 KPa. A mass 72.40022026 kg falls from a height of 0.85 m to the center of a horizontal platform mounted on five helical springs. At impact each springs deflects 65 mm. Assume spring index of 8.