The balanced equation for the combustion of butane, C4H10, is shown below. For your convenience, the molar mass of each substance is shown below their formulas (in purple). Use this information to make the requested calculation: 2 CH10(g) + 13 02(g) -> 8 CO2(g) + 10 H20(1) 58.124 32 44.011 18.016

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Chapter9: Chemical Quantities
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The balanced equation for the combustion of butane, CaH10, is shown below. For your convenience, the molar mass of each substance is
shown below their formulas (in purple). Use this information to make the requested calculation:
2 CH10(g) + 13 02(g)
--> 8 CO2(g) + 10 H20(1)
58.124
32
44.011
18.016
What mass of butane, in kg, will be needed to react fully with 250 L of oxygen gas?
Transcribed Image Text:The balanced equation for the combustion of butane, CaH10, is shown below. For your convenience, the molar mass of each substance is shown below their formulas (in purple). Use this information to make the requested calculation: 2 CH10(g) + 13 02(g) --> 8 CO2(g) + 10 H20(1) 58.124 32 44.011 18.016 What mass of butane, in kg, will be needed to react fully with 250 L of oxygen gas?
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