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Name: The average distance of the planet Mercury from the sun is 0.39 times
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Description: The average distance of the planet Mercury from the sun is 0.39 times the average distance of the earth from the sun.How long is a year on Mercury in units of earth years?___ earth years

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Physics

The average distance of the planet Mercury from the sun is 0.39 times the average distance of the earth from the sun.How long is a year on Mercury in units of earth years?___ earth yea

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter1: Introduction And Vectors

Section: Chapter Questions

Problem 5OQ

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Similar questions

One full year is 365.26 days. Using this number and the distance between the sun and the earth, calculate the Earth’s velocity. Question 8 options: 21.4 km/s 23.7 km/s 26.2 km/s 29.8 km/s 31.9 km/s
A climber who is 75 kgs in mass reaches the peak of a mountain. If the mutual attraction between the climber and the Earth is 735.09 N, how tall is the mountain in meters? radius of the Earth = 6.38 x 106 m mass of the Earth = 5.98 x 1024 kgs
The weight of an object at the surface of a planet is proportional to planet's mass and inversely proportional to the square of the radius of the planet. Jupiter's radius is 11 times Earth's and its mass is 320 times Earth's. An apple weighs 2.20 N on Earth. How much would it weigh on Jupiter?
The planet Mars has a mass of 6.42x10^23 kg and a radius of 3.38x10^6 m. Determine how much a 50 kg person would weigh on Mars.
According to Newton's law of universal gravitation, the attraction force between two bodies is given by: where mi and m2 are the masses of the bodies, r is the distance between the bodies, and G=6.67 × 10-" N-m²/kg² is the universal gravitational constant. Determine how many times the attraction force between the sun and the Earth is larger than the attraction force between the Earth and the moon. The distance between the sun and Earth is 149.6 x 10°m, the distance 28 between the moon and Earth is 384.4 × 10°m, mEarth = 5.98 x 10“ kg, = 2.0 x 10" kg, and mn =7.36 x 102 kg.
Tidal friction is slowing the rotation of the Earth. As a result, the orbit of the Moon is increasing in radius at a rate of approximately 4 cm/year. Assuming this to be a constant rate, how many years will pass before the radius of the Moon's orbit increases by 3.84×106 m (1%)?
A patient’s temperature was 97.0 °F at 8:05 A.M. and 102.0 °F at 12:05 P.M. If the temperature change with respect to elapsed time was linear throughout the day, what would the patient’s temperature be at 3:35 P.M.?
Estimate the number of steps you would have to take to walk a distance equal to the circumference of the Earth. (We estimate that the length of a step for an average person is about 18 inches, or roughly 0.5 m. The radius of the Earth is 6.38 x 106 m.) 105 steps 108 steps 1011 steps 1015 steps O 1020 steps
On planet Z, the standard unit of length is the foose. Ann the Astronaut is 5.2 feet tall on Earth. She lands on planet Z and is measured to be 88 foosi tall. Her partner Rachael is 92 foosi tall. How tall is Rachael on Earth?
When you are at a height x above the surface of the earth, your weight can be found by the following formula: W(x) = mg (1 + x/R) −2 , where m is the mass of your body, g is the acceleration due to gravity, and R is the radius of the earth. For example, W(0) is your weight when you are on the surface of the earth and W(R) is your weight when you are at the height R above the surface of the earth (yes, you are far away from the earth’s atmosphere). In this question, we will approximate W(0) and W(R). (a) Find L0(x), the linear approximation of W(x) at x = 0. (b) Use L0(x) to approximate W(0) and W(R). Which approximation is more accurate? Why? (c) Find LR(x), the linear approximation of W(x) at x = R. (d) Use LR(x) to approximate W(0) and W(R). Which approximation is more accurate? Why?
The average distance between Earth and the Sun is 1.5 ✕ 1011 m. (a) Calculate the average speed of Earth in its orbit (assumed to be circular) in meters per second (b) What is this speed in miles per hour? Please answer B
Until 1883, every city and town in the United States kept its own local time. Today, travelers reset their watches only when the time change equals 1.0 h. How far, on the average, must you travel in degrees of longitude between the time-zone boundaries at which your watch must be reset by 1.0 h? (Hint: Earth rotates 360° in about 24 h.)