Question 2 When you lift an object by moving only your forearm, the main lifting muscle in your arm is the biceps. Suppose the mass of a forearm with hand is 1.80 kg. If the biceps is connected to the forearm a distance of 2.50 cm from the elbow, what is the magnitude of the torque exerted by the biceps to hold a 44.5 N (about 10 lbs) ball at the end of the forearm at distance of 35.0 cm from the elbow, with the forearm parallel to the floor, in N-m? Use g = 10.0 m/s². Your answer needs to have 3 significant figures, including the negative sign in your answer if needed. Do not include the positive sign if the answer is positive. No unit is needed in your answer, it is already given in the question statement. driceps Biceps ∙drall- Selected Answer: Question 3 When you lift an object by moving only your forearm, the main lifting muscle in your arm is the biceps. Suppose the mass of a forearm with hand is 1.80 kg. If the biceps is connected to the forearm a distance of 2.50 cm from the elbow, how much force must the biceps exert to hold a 44.5 N (about 10 lbs) ball at the end of the forearm at distance of 35.0 cm from the elbow, with the forearm parallel to the floor, in Newtons? Use g = 10.0 m/s². > Your answer needs to have 3 significant figures, including the negative sign in your answer if needed. Do not include the positive sign if the answer is positive. No unit is needed in your answer, it is already given in the question statement. -Biceps -drall *

The figure is a section of a conducting rod of radius R₁ = 1.20 mm and length L = 13.00 m inside a thin-walled coaxial conducting cylindrical shell of radius R2 = 11.1R₁ and the (same) length L. The net charge on the rod is Q₁ = +3.70 × 10-12 C; that on the shell is Q2 = -2.33Q1. What are the (a) magnitude E and (b) direction (radially inward or outward) of the electric field at radial distance r = 2.33R2? What are (c) E and (d) the direction at r = 5.07R₁? What is the charge on the (e) interior and (f) exterior surface of the shell? R R₁ (a) Number i Units (b) (c) Number i Units Q2 > >

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Find the dot product  Item no 2 given (incase they were not visible)  Ax = 16 Bx = 9 Ay = 12 By = 12

(3) The speed of light in vacuum, c, is 3 X 105 km/s and 1 kilometer = 1000 meters. How many Joules of energy are released if 2 kg of matter are converted into energy at 0.1% efficiency? First convert c to units of meters/second: c = 3 x 105 km/s x 1000 m/km = 3 x 108 m/s. Then express efficiency (eff) in decimal terms: eff = 0.001. In this type of problem, the mass/ energy equivalence equation is written as: E = (eff) mc2 Joules,

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(a) Number i Units (b) Number i Units (c) (d) (e) > > > >

In Figure (a), string 1 has a linear density of 2.08 g/m, and string 2 has a linear density of 4.84 g/m. They are under tension due to the hanging block of mass M = 677 g. Calculate the wave speed on (a) string 1 and (b) string 2. (Hint: When a string loops halfway around a pulley, it pulls on the pulley with a net force that is twice the tension in the string.) Next the block is divided into two blocks (with M, + M2 = M) and the apparatus is rearranged as shown in Figure (b). Find (c) M1 and (d) M2 such that the wave speeds in the two strings are equal. - String 1 String 2 Knot M (а) - String 1 String 2 M1 M2 (b)

Thank you- what would be the unit for (f) if the number is 0?