College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- 1. Given the circuit shown below where V=20.0 V, R=210. 2, C₁ = 22.0 μF, and C₂ = 35.0 µF. R wwwwwww a. wwwwww R C₂ C₂ S Consider the case when no charges stored in all capacitors at t = 0. How much energy is stored in capacitor C₁ at t = 3.00 ms?arrow_forwardTwo capacitors of capacitance C₁ = 100 nF and C₂ = 5 µF are connected in series across a cell with emf V = 5V. What is the voltage across C₂?arrow_forwardConsider the circuit shown in the figure. (Assume that C₁ = 3 µF, C₂ = 6 µF, C3 = 5 μF, and C4 = 4 μF.) C₁ C₂₂ C₂ Determine the following. (a) the total energy (in mJ) stored in the system mJ C3 C4 (b) the energy (in mJ) stored by each capacitor C₁ mJ mJ mJ mJ = = Cg II + 90.0 V = C4 (c) Which statement is true regarding the energy of the system and the individual capacitors? O The sum of the energies stored in the individual capacitors is less than the total energy stored by the system. The sum of the energies stored in the individual capacitors is greater than the total energy stored by the system. O The sum of the energies stored in the individual capacitors equals the total energy stored by the system.arrow_forward
- Consider the circuit shown in the figure, with C₁ = 2.42 μF and C₂ = 7.54 µF. 2 2.00 µF 6.00 µF + 90.0 V 1 C₂ (a) Find the equivalent capacitance (in µF) of the system. UF (b) Find the charge (in μC) on each capacitor. 2.42 μF capacitor UC 6.00 μF capacitor 7.54 µF capacitor 2.00 µF capacitor 오오오 (c) Find the potential difference (in V) on each capacitor. 2.42 μF capacitor V 6.00 μF capacitor V 7.54 µF capacitor V 2.00 uF capacitor V (d) Find the total energy (in m3) stored by the group. mJarrow_forwardIn the circuit shown in Figure C₁ = 15.0μF, C₂ = 20.0μF, R₁ = 30.0Q2, R₂ = 50.0Q2. Both capacitors are initially charged to Vi = 45.0 V. a) Calculate the equivalent capacitance and the equivalent resistance. b) Calculate the charge accumulated on each capacitor. c) Calculate the time after closing the switch at which the potential across each capacitor will be reduced to V₁ = 10.0 V. S R₁ R₂ C₁- C₂ ‘TTarrow_forwardHW #4arrow_forward
- Consider the circuit shown in the figure, with C₁ = 4.62 μF and C₂ = 7.44 μF. 2.00 µF 6.00 µF + 90.0 V C₂ (a) Find the equivalent capacitance (in µF) of the system. μF (b) Find the charge (in µC) on each capacitor. 4.62 μF capacitor 6.00 μF capacitor 7.44 μF capacitor 2.00 μF capacitor 9999 μC μC μC (c) Find the potential difference (in V) on each capacitor. 4.62 µF capacitor V 6.00 μF capacitor V 7.44 μF capacitor V 2.00 μF capacitor V (d) Find the total energy (in mJ) stored by the group. mJarrow_forwardProblems 21-15 refer to the following diagram and situation. In the circuit below, AV bat = 12.0 V and the capacitors have the values shown below. 8.60 μF HHE 4.80 μF 6.20 μF 11.8 με HH Problem 21: What is the charge on the 8.60 μF capacitor? a. 16.3 μC b. 26.3 μC Problem 22: What is the charge on the 4.80 µF capacitor? a. 16.3 μC b. 26.3 μC Problem 23: What is the charge on the 6.20 μF capacitor? a. 14.1 μC b. 24.1 μC Problem 24: What is the charge on the 11.8 μF capacitor? a. 14.1 μC b. 24.1 μC Problem 25: What is the charge on the 3.50 µF capacitor? a. 12.2 μC b. 22.2 μC 3.50 μF ㅓㅏ AV bat c. 36.3 μC c. 36.3 μC c. 34.1 μC c. 34.1 μC c. 32.2 μC d. 44.1 μC d. 44.1 μC d. 44.1 μC d. 44.1 μC d. 42.2 μCarrow_forwardCapacitors C₁ = 300μF and C₂ = 100μF and a 4V battery are connected in series. The respective voltages V₁ and V₂ across the capacitors are: OV₁ = 3volt & V₂ = 1volt OV₁ = 2volt & V₂ = 2volt OV₁ = 1volt & V₂ = 3voltarrow_forward
- Consider the circuit shown in the figure, with C₁ = 6.92 µF and C₂ = 6.84 µF. 2.00 µF 6.00 µF + 90.0 V (a) Find the equivalent capacitance (in μF) μF (b) Find the charge (in µC) on each capacitor. 6.92 μF capacitor 6.00 μF capacitor 6.84 μF capacitor 2.00 μF capacitor mJ 9999 (c) Find the potential difference (in V) on each capacitor. 6.92 μF capacitor V 6.00 μF capacitor V 6.84 μF capacitor 2.00 μF capacitor the system. V (d) Find the total energy (in mJ) stored by the group.arrow_forwardFor the circuit shown in the figure below, (V = 11.6 V) 0.30 uF 1.0 рF V 0.25 uF (a) Find the equivalent capacitance between the terminals µF (b) Find the charge stored on the positively charged plate of each capacitor 0.3 иF сараcitor µč 1.00 uF саpаcitor µC О.250 uF саpacitor µC (c) Find the voltage across each capacitor 0.3 иF сарacitor 1.00 иF саpacitor V 0.250 иF сараcitor V (d) Find the total stored energy. еВookarrow_forwardSwitch S1 has been closed and S2 has open for a long time until the capacitors are fully charged. At t=0, S1 is opened and S2 is closed. If e=12V, C₁=4mF and C₂=8mF, R₁=1.51k0 and R₂=4.38 k0; what is the time constant for t>0 in units of seconds? Please express your answer using two decimal places. E R₁ S₁ ㅏㅏ C₂ C₁ a b S R₂arrow_forward
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