That's enough for you! def first_preceded_by_smaller(items, k=1): Find and return the 0irst element of the given list of items that is preceded by at least k smaller elements in the list. These required k smaller elements can be positioned anywhere before the current element, not necessarily consecutively immediately before that element. If no element satisfying this requirement exists in the list, this function should return None. Since the only operation performed for the individual items is their order comparison, and especially no arithmetic occurs at any point during execution, this function should work for lists of any types of elements, as long as those elements are pairwise comparable with each other. items k Expected result [4, 4, 5, 6] 2 5 [42, 99, 16, 55, 7, 32, 17, 18, 73] 3 18 [42, 99, 16, 55, 7, 32, 17, 18, 73] 8 None ['bob', 'carol', 'tina', 'alex', 'jack', 'emmy', 'tammy', 'sam', 'ted'] 4 'tammy' [9, 8, 7, 6, 5, 4, 3, 2, 1, 10] 1 10 [42, 99, 17, 3, 12] 2 No

That's enough for you!

Find and return the 0irst element of the given list of items that is preceded by at least k smaller elements in the list. These required k smaller elements can be positioned anywhere before the current element, not necessarily consecutively immediately before that element. If no element satisfying this requirement exists in the list, this function should return None.

Since the only operation performed for the individual items is their order comparison, and especially no arithmetic occurs at any point during execution, this function should work for lists of any types of elements, as long as those elements are pairwise comparable with each other.