Implement the following function. Hint: You should use a dictionary. def word_pattern (pattern: str, words: List [str]) -> bool: "Given a pattern and a word list, determine if the word list follows the same pattern. That is to say, ensure that pattern [j] == pattern [k] only when words [j] == words [k] pattern [j] != pattern [k] means words [j] != words [k] Precondition: Assume pattern is all lowercase letters. >>> word_pattern ('aaaa', ['cat', 'cat', 'cat', 'cat']) Tuu and

Implement the following function. Hint: You should use a dictionary. def word_pattern (pattern: str, words: List [str]) -> bool: "Given a pattern and a word list, determine if the word list follows the same pattern. That is to say, ensure that pattern [j] == pattern [k] only when words [j] == words [k] pattern [j] != pattern [k] means words [j] != words [k] Precondition: Assume pattern is all lowercase letters. >>> word_pattern ('aaaa', ['cat', 'cat', 'cat', 'cat']) Tuu and

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Write a function sort_and_return_in_pairs_list for example:[12, 13, 11, 15] return =>(11.12) and (12,13)[14,19,16,18,17,15] return =>(14.15) (16.17) (18.19)
Implement a list of employees using a dynamic array of strings.Your solution should include functions for printing list, inserting and removingemployees, and sorting lists (use Bubble sort in C++ language).Keep list of employees sorted within the list after insertion.See the following example:How many employees do you expect to have?5 (Carriage Return)Menu :1 . Print full list of employees2 . Insert new employee3 . Remove employee from list0 . Exit2 (Carriage Return)Input name of new employee : MikeMenu :1 . Print full list of employees2 . Insert new employee3 . Remove employee from list0 . Exit1(Carriage Return)1 . MaryMenu :1 . Print full list of employees2 . Insert new employee3 . Remove employee from list0 . Exit
given a dictionary of characters with their favorite foods. sort the characters and their favorite foods. return a dictionary where the keys are characters and the values are the friends who like the same foods. if more than one character likes the same food sort alphabetically. >>> friends1 = {"Famy": ["pizza", "chocolate"], "Nihal": ["chocolate","hotdog"], "Amy":["chocolate", "chips"]} >>> friendsfoods(friends1) {'pizza': ['Famy'], 'chocolate': ['Amy', 'Famy', 'Nihal'], 'hotdog': ['Nihal'], 'chips': ['Amy']} >>> friends2 = {'Alissa': ['pizza', 'hotdog'], 'Arun': ['pizza', 'chips'], 'Michele': ['icecream', 'burger', 'fries']} >>> friendsfoods(friends2) {'pizza': ['Alissa', 'Arun'], 'hotdog': ['Alissa'], 'chips': ['Arun'], 'icecream': ['Michele'], 'burger': ['Michele'], 'fries': ['Michele']} Subject: Python Programming
def sort and_pop(x: list, i: int) -> list: x.sort() return x.pop(i) # Dan's code lst = [23, 17, 3, 13, 11, 5, 7, 2, 19, 1] lst = sort_and_pop(lst, 5) lst = sort_and_pop(lst, 2) II I| || If you run this code, you'll find that it produces an error. Surprise! According to the type contract, Dan's Code should work. But it doesn't, because the function type contract has faulty type annotations. Correct the function type contract so that it's clear from the type contract that Dan's code will not work. (Dan's Code will and should remain an incorrect use of the function!) TODO: Write a new type contract"" "
Think about the following example: A computer program builds and modifies a linked list like follows: Normally, the program would keep tabs on two unique nodes, which are as follows: An explanation of how to use the null reference in the linked list's node in two common circumstances
def print_categories(main_list): for i in all_categories: main_list = all_categories.split() print(i,":",all_categories[i]) return "" """ Given a list of lists, for each list stored in main_list, output its contents as follows: f"{index of category}. {item[0]} - {item[1]}%". note that indexing must start at 1 for the first item, not 0, which is first item's actual index in main_list. If `main_list` is empty, the function prints "There are no categories." Returns the number of categories.
Assume, you have been given a dictionary where the keys present the name of the father and the value is a list of names of the sons of that person. For example A has 3 sons namely X, Y, and Z. Again X has three sons namely E, F, and G. So, A is the grandfather of E, F, and G. family = {"A" : ["X", "Y", "Z"], "B": ["M", "N"], "W" : ["A", "B"], "X" : ["E", "F", "G"]} You need to write a code which takes an input and prints the names of all his grandsons in the format shown in output samples. If he does not have any grandchildren just print “Get your sons married first! Wanna_be_grandpa!!” You can assume the input will always be a key from the dictionary. But we will check your code with a different dictionary. So do not write a code for this particular dictionary only.
struct insert_at_back_of_sll { // Function takes a constant Book as a parameter, inserts that book at the // back of a singly linked list, and returns nothing. void operator()(const Book& book) { /// TO-DO (3) /// // Write the lines of code to insert "book" at the back of "my_sll". Since // the SLL has no size() function and no tail pointer, you must walk the // list looking for the last node. // // HINT: Do not attempt to insert after "my_sll.end()". // ///// END-T0-DO (3) ||||// } std::forward_list& my_sll; };
PYTHON: Please fix my code to print the correct traversals, especially at the def functions, because I could not print the correct results of the inorder, postorder, and preorder traversals from the user input. #POSTORDERclass Node: def __init__(self, data): self.left = None self.right = None self.data = data # Insert Node def insert(self, data): if self.data: if data < self.data: if self.left is None: self.left = Node(data) else: self.left.insert(data) elif data > self.data: if self.right is None: self.right = Node(data) else: self.right.insert(data) else: self.data = data # Print the Tree def PrintTree(self): if self.left: self.left.PrintTree() print(self.data),…
Alert dont submit AI generated answer. please explain in details. Please print fixlist function so it would print out both lists a = [1, 5, 3, 6] b = [3, 5, 3 ,2, 4, 6, 8, 5, 2] def printList(list): for i in range(9): print(list[i]) print("End of List" print list(a) printList(b) Expected output: 1 5 3 6 End of List 3 5 3 2 4 6 8 5 2
PYTHON CS1 PROBLEM Define a function that takes a dictionary gdict as a parameter and returns a list of values that are associated with only a single key in the dictionary. For example: 1. If gdict = {"a":3, "b": 4, "x": 3, "z": 5, "k": 4, "c": 1} then your function should return the list [1, 5]. 3 and 4 are not in the returned list because they are associated with more than one key. 2. If gdict = {"a":3, "b": 4, "x": 3, "k": 4) then your function should return the list []. 3. If gdict = {} then your function should return the list [].
def reverse_list (1st: List [Any], start: int, end: int) -> None: """Reverse the order of the items in list , between the indexes and (including the item at the index). If start or end are out of the list bounds, then raise an IndexError. The function must be implemented **recursively**. >>> lst ['2', '2', 'v', 'e'] >>>reverse_list (lst, 0, 3) >>> lst ['e', 'v', 'i', '2'] >>> lst [] >>>reverse_list (lst, 0, 0) >>> lst [0] >>> Ist = [] >>> reverse_list (lst, 0, 1) Traceback (most recent call last): IndexError #1 #1