T2 T1 di 'd2

Q: A spring is extended by 50 mm with the application of a force of 10N, and the spring constant is…

A:

Q: A 3 kg mass is suspended from a spring with k = 80 N/m. What will be the stretch in the spring? O A)…

A:

Q: Problem 10: A block of mass m = 0.22 kg is set against a spring with a spring constant of k = 513…

A: mass (m) = 0.22 kg spring constant of first spring (k1) = 513 N/m Compression in first spring (x1) =…

Q: A 2.00-kg package is released on a 53.1° incline, 4.00 m from a long spring with force constant 1.20…

A: Given a  2.00 kg package is released on a 53.1◦ incline, 4.00 m from a long spring with force…

Q: A horizontal spring with force constant k = 58.0 N/m is used to accelerate a 0.520-kg mass on a…

A: Write the given values with the suitable variables. k=58 N/mm=0.52 kgx=5.75×10-2 m Here, k is the…

Q: (a) Find the magnitude of the force required to compress the spring by 4.10 cm from its unstretched…

A: a) The spring force required to compressed by 4.10(x) cm from unstetched length, F= kx, where k=129…

Q: When you hang a 100 g mass from a spring, the spring stretches 2 cm. If you remove the 100 g mass…

A:

Q: The block in the figure below rests on a frictionless surface. Find its instantaneous acceleration…

A: Compression in left spring = 4.42cm Stretching in right spring = 11.5cm Mass of box= 2kg

Q: mass attached (kg) = . 061 Displacement (m) = .2 What is the Spring

A: the restoring force Fx​ is directly proportional to the displacement x. This restoring force and the…

Q: cm 10.0 20.0 2. The drawing shows three identi- cal springs hanging from the ceiling. Nothing is…

A: Given Data: The unstretched length is, l=20 cm The weight lift by the second spring is, F2=4.50 N…

Q: A 1.60-kg object is held 1.40 m above a relaxed, massless vertical spring with a force constant of…

A: mass of object (m) = 1.60 kg height of object above spring (h) = 1.40 m force constant (k) = 300 Nm…

Q: A horizontal spring (with a spring constant of 1000 N/m) is compressed by some amount, A, by a mass…

A: GIVEN: Force constant of spring = 1000N/m mass = 3kg velocity of mass = 15m/s

Q: A 0.51-kg block attached to a spring with force constant 140 N/m is free to move on a frictionless,…

A: (a) Calculate the magnitude of force on the block. |Fs|=kx Here, k is the spring constant and x is…

Q: When you hang a 100 g mass from a spring, the spring stretches 2 cm. If you remove the 100 g mass…

A: Given data: Known Mass (m1) = 100 g = 0.100 kg Stretch in spring (x1) = 2 cm = 0.02 m Unknown mass =…

Q: To use the equations of equilibrium to analyze a system containing a wedge and to determine the…

A: Using spring combo Value of p= 397 N

Q: What mass must be added to a spring with k = 80 N/m to stretch the spring 15.0 cm? O A) 1200 kg B)…

A: Given data: Spring constant is, k=80 N/m. Stretching distance is, x=15.0 cm=0.15 m.

Q: A pendulum consists of a 2 kg bob attached to a light string of length 6.0 m.  The bob is struck…

A:

Q: The adjacent figure shows two configurations (a) of a spring () that is hung (es) vertically. In A,…

A: Answer               D.  147

Q: 4. Springs AB and CD have a stiffness ofk = 300 N/m and k' = 200 N/m, respectively, and both springs…

A: Given: Stiffness of AB, k = 300 N/m Stiffness of CD, k' = 200 N/m Length of both spring = 600 mm

Q: A small block of mass M = 150 g is placed on top of a larger block of mass 3M which is placed on a…

A:

Q: The diagram shows a horizontal spring attached to a block. The block’s equilibrium position is at C,…

A: Given, A block performing SHM Equilibrium at C Extreme position is at E

Q: The length of a spring increases by 5.80 cm from its relaxed length when a mass of 1.40 kg is…

A:

Q: A 2.00 kg package is released on a 53.1° incline, 4.00 m from a long spring with force constant 1.20…

A: Given that, m=2 kg, θ=53.10, l=4 meter ,k=120N/m, μs=0.40, μk=0.20 a) Work done by non-conservative…

Q: A 10-kg block is attached to one end of a horizontal spring on a level, frictionless surface. The…

A:

Q: A 1.20-kg object is held 1.05 m above a relaxed, massless vertical spring with a force constant of…

A:

Q: The graph hanging Force vs spring Displacement( extension AX) is given below. Find the spring…

A:

Q: Imm וננננ mm 30 10 60 W 110 N 240 N A spring with a pointer attached is hanging next to a scale…

A: The force equation for the given cases, From equation (I) and (II), the values of extension of…

Q: ( ANSWER e,f, and g ), a is given ) You have two equal masses m1 and m2 and a spring with a…

A: Given: The mass m1 = m2 = 0.500 kg. The spring constant k = 290 N/m. You now pull the mass m2 down a…

Q: The springs used in ballpoint pens are some of the weaker examples found in practical applications.…

A: The force applied to the spring will be equal to the weight of the resting mass. F=mg=0.005 kg9.8…

Q: A block of mass m2 = 10.0 kg, at rest on a horizontal surface that has negligible friction, is…

A: using conservation of momentum mu + MV = (m +M) v 14(3.2) + 10(0) = (14+10)v v = 1.87 m/s (combined…

Q: A horizontal spring-mass system consists of a spring and a weight attached to the end of it. The…

A:

Q: A spring with a spring constant of k = 192 N/m is initially compressed by a block a distance d =…

A:

Q: A spring has a length of 0.260 m when a 0.300 kg mass hangs from it, and a length of 0.750 m when a…

A: Given: Mass1, m1=0.300 kg Length1, L1=0.260 m. Mass2, m2=2.60 kg Length2, L2=0.750 m Required:…

Q: A 1.60-kg object is held 1.30 m above a relaxed, massless vertical spring with a force constant of…

A: 5.  mass, m = 1.6 kg  height, h = 1.3m  spring constant, k = 340 N/m

Q: The springs of a pickup truck act like a single spring with a force constant of k = 1.25 × 105 N/m.…

A: a)the magnitude of  restoring force is equal to the weight of the load

Q: A 1.40-kg object is held 1.00 m above a relaxed, massless vertical spring with a force constant of…

A: Given  Initial height of mass is 1m Final height is -X m Where X is the compression in spring. K =…

Q: he graph shows the force F that an archer applies to the string of a long bow versus the string's…

A: in the given fig  force and displacement has linear relationship  so we can write  F ∝ - x  F= K x F…

Q: The system shown in the figure is in equilibrium. Masses mj& m2 are 2 kg and 8 kg respectively.…

A: Draw the free-body diagram of the 2 kg mass.

Q: The diagram shows a simple pendulum consisting of a mass M = 1.19 kg suspended by a thin string with…

A:

Q: A spring has a length of 0.270 m when a 0.300 kg mass hangs from it, and a length of 0.750 m when a…

A:

Q: A pendulum is pulled back at an angle of 20 degrees and released from rest. As the mass at the end…

A: A pendulum is pulled back at an angle of 20 degrees and released from rest.  To find = Which if the…

Q: A block of mass 1.3 kg is attached to a horizontal spring that has a force constant 900 N/m as shown…

A: a)the expression for the retarding force is

Q: Based on the graph below, what is the spring constant of the spring? Force vs Cumulative Elongation…

A:

Q: This problem uses the ideal spring force in one dimension.  F = -kx, where x is the deviation from…

A:

Q: An object is held against a compressed spring. When released from rest it is pushed to the right…

A: Since you have posted a question with a multiple sub parts, we will solve first three sub - parts…

Q: what is the velocity of the block vf in m/s?

A: Friction will perform negative work and decrease total mechanical energy of spring block system .…

Spring Potential Energy

The potential energy is the energy possessed by a body by virtue of its position or the energy held by the object due to its position relative to other objects, its force like stresses, charge, and other factors affecting the particles of the body. The potential energy is the measure of the net work done by or on the body. The spring potential energy is the potential energy stored due to the deformation of an elastic spring and this elasticity is due to the stretched spring. The elasticity is the ability of a solid-state matter to come back to its equilibrium position or original position after any kind of external force is acted on it. It is also known as Elastic potential energy. The potential energy here is caused due to the displacement of the spring from its equilibrium position to another position and this potential energy is equal to the net work done due to the stretching of the spring. It also resembles the same mechanics of the oscillation of a simple pendulum, where due to the external force, the object moves from its equilibrium position to its maximum ends and the periodic motion continues till it comes back to the equilibrium position to rest.