2. A symmetric dielectric slab waveguide is to guidelight at wavelength A= 1.30 µm. The slabthickness is to be d = 5.00 um, and the refractiveindex of the surrounding material is n2 = 1.450.%3DDetermine the maximum allowable refractiveindex of the slab material that will allow single TEand TM modeoperation.

The equation for the maximum allowable refractive index is given as n1<λ2d2+n22λ= wave length…

Answered: symmetric dielectric slab

Engineering

Electrical Engineering

symmetric dielectric slab

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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Concept explainers

Dielectric Breakdown

A dielectric is a material with low electrical conductivity and so is classified as an insulator. Dielectric materials are used to block the flow of electricity through them, allowing them to behave as an insulators. They can also be used to store electric charge or improve capacitance.Dielectrics have no free electrons for conduction because electrons are tightly bound to the nucleus. Because dielectrics contain a small number of electrons for electrical conductivity, they have a dipole. The two primary roles of dielectrics in electrical devices are insulation and electrical energy storage. An electric field polarizes the dielectric, and the polarization of the molecules allows dielectric materials to store charge.

Question

2. A symmetric dielectric slab waveguide is to guide
light at wavelength A= 1.30 µm. The slab
thickness is to be d = 5.00 um, and the refractive
index of the surrounding material is n2 = 1.450.
%3D
Determine the maximum allowable refractive
index of the slab material that will allow single TE
and TM mode
operation.

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