Suppose the initial speed of the proton in the figure( Figure 1) is decreased. Part A Does the time spent in each of the field regions increase, decrease, or stay the same? Figure 1 of 1 B₂ B₁ B3 increases decreases stays the same Submit Request Answer Part B Choose the best explanation from among the following: With a smaller speed the proton is forced out of each magnetic region more quickly, which results in a decrease in the time. The time for an orbit in a magnetic field is independent of speed. Therefore, the time the proton spends in each of magnetic regions is the same no matter what its speed. The proton moves more slowly, and therefore the time spent moving through each of magnetic regions will increase. Submit Request Answer Provide Feedback Next >

Suppose the initial speed of the proton in the figure( Figure 1) is decreased. Part A Does the time spent in each of the field regions increase, decrease, or stay the same? Figure 1 of 1 B₂ B₁ B3 increases decreases stays the same Submit Request Answer Part B Choose the best explanation from among the following: With a smaller speed the proton is forced out of each magnetic region more quickly, which results in a decrease in the time. The time for an orbit in a magnetic field is independent of speed. Therefore, the time the proton spends in each of magnetic regions is the same no matter what its speed. The proton moves more slowly, and therefore the time spent moving through each of magnetic regions will increase. Submit Request Answer Provide Feedback Next >

Inquiry into Physics

8th Edition

ISBN:9781337515863

Author:Ostdiek

Publisher:Ostdiek

Chapter7: Electricity

Section: Chapter Questions

Problem 10Q

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Reclung.c A on ri gle Figure 1 2. The circuit shown above is constructed with two 6.0 V batteries and three resistors with the values shown. The currents 1₁, 12, and 13 in each branch of the circuit are indicated. 2 GEOMETRY AND TRIGONOMETRY Circle A = ²² C = 2πr Cy.inder bh - re Rectangular Solid Vlh Sphere 1. Using Kirchhoff's rules, write, but DO NOT SOLVE, equations that can be used to solve for the current in each resistor. ii. Calculate the current in the 200 9 resistor. iii. Calculate the power dissipated by the 200 2 resistor. V = ar²l S.. Figure 2 The two 6.0 V batteries are replaced with a battery with voltage & and a resistor of resistance 50 2, as shown above. The voltmeter V shows that the voltage across the 200 £2 resistor is 4.4 V. (b) Calculate the current through the 50 2 resistor. (c) Calculate the voltage & of the battery. V=² S = 4; 7² Rig Triangle 2 +6² = c² sin = COS== tan 8 = OJA b C 2m. a b 6.0 V 7,4 & A - area C=circumference h-hei £= le L W = IUL r=fuu.0…
Using the given charge-to-mass ratios for electrons and protons, and knowing the magnitudes of their charges are equal, what is the ratio of the proton's mass to the electron's? (Note that since the charge-to-mass ratios are given to only three-digit accuracy, your answer may differ from the accepted ratio in the fourth digit.)
A "cathode ray tube" (CRT), as shown in the image at right and the diagram below, is an evacuated glass tube. A current runs through a filament at the right end of the tube. When the metal filament gets very hot, electrons occasionally escape from it. These electrons can be accelerated away from the filament by Coil applying a potential difference AVacc across the metal plates labelled A and B in the diagram. Accelerating plates The electrons pass through a hole in plate B and enter the glass sphere. There they pass between the two horizontal metal "deflection" plates labelled C and D. A potential difference AVdef can be applied across these plates, to deflect the beam of electrons. Coil In front of and in back of the glass sphere are two coils, through which current Deflection plates can be run to produce a magnetic field in the region between the deflection plates. The coils are oriented so they both produce magnetic fields into the page in this region. AV sce 米 a Oj out of the page…
i cant apply the formula please help.i added two important photos about this question. Now in velocity selector region, determine the magnitude and the directions of magnetic, electric fields, length and the voltage (which will create electric field) that you need to select ions with this velocity only .
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In the figure below, a positive charge of 20 mC and 1g of mass is moving as shown in the figure with speed of 300km/h the magnetic field of 10 T is directed out of the page. Calculate the magnetic force and draw the trajectory of the charge inside the magnetic field. What is this trajectory radius? Calculate and draw the direction of the needed electric field to keep this charge moving in straight line.
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B INSTRUCTION Solve the following problems. ANSWER ONLY TWO OUT OF THREE QUESTIONS. Show your complete solutions. NOT FOLLOWING OF INSTRUCTIONS will be a deduction of 10 POINTS from the total score. 1.A proton enters a magnetic tield of flux density 1.5 Wb/m² with a vetocity of 2.0 x 107 m/s at an angle of 30° with the field. Compute the force on the proton. 2.A steady current of 2 A in a coil of 400 turns causes a flux of 104 wb to link (pass through) the loops of the coil. Compute the average back emf induced in the coit it the current is stopped in 0.08 seconds. 3. A coil of 50 loops is pulled in 0.020 seconds from between the poles of a magnet, where its area intercepts a flux of 3.1 x 10-4 Wb, to a place where the intercepted flux is 0.10 x 10-4 Wb. Determine the average emf induced.
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Please solve the all sub parts ... I'm needed max in 20 please and no reject I'm needed the answer thank u Consider a system consisting of three current-carrying wires, one very long straight wire and two coiled wires as shown in the figure. The three wires are insulated from each other and there is no friction between the wires. R = 70 cm Given vacuum permeability is u0 = 4π x 10^ - 7 * T * m / A A. The magnitude of the magnetic field at the point P by the current l₁ = 4 A is..... uT B. So that the magnitude of the magnetic field at point P by current I1 is equal to the magnitude of the magnetic field by current , then the ratio I2/I1 is... C. For and according to problems a and b while I3=I2 then the magnitude of the magnetic field at point P by all current-carrying wires is... uT D. If I3 = 2l2 , then the two wires are circular.... Write your answer in numbers: -1 if the two wires are moving away from each other, 1 if the two wires are close to each other, and 0 if the two…
Homework-2 (page 2 of 5)- Google Chrome od/quiz/attempt.php?attempt3D186679&cmid%3D3903&page%3D1 Physics II (CRN: 50010) A partidle with charge q = 1.1 C and a long wire carrying current I = 5 A is on the ry-plane at the moment the charge is at point P at distance d = 0.4 cm from the wire and has velocity v = 1.7 m/s in the a-direction. X. I What is the magnitude of the magnetic force acting on the charge in units of nanonewtons? (Ho = 4a × 10 7T- m/A) 节 Answer: Next pac