A cook puts 5.80 g of water in a 2.00-L pressure cooker that is then warmed to 530°C. What is the pressure inside the container? (Assume room temperature is 20°C kPa

I Review I Cons A weather balloon rises through the atmosphere, its volume expanding from 3.6 m to 12 m3 as the temperature drops from 20 °C to -10 °C. Part A For the steps and strategies involved in solving a similar problem, you may view a Video Tutor Solution. If the initial gas pressure inside the balloon is 1.0 atm, what is the final pressure? Express your answer in atmospheres. n ΑΣφ ? P = atm Submit Request Answer

An automobile tire is inflated with air originally at 10.0°C and normal atmospheric pressure. During the process, the air is compressed to 27.0% of its original volume and the temperature is increased to 39.0°C. (a) What is the tire pressure in pascals? Pa (b) After the car is driven at high speed, the tire's air temperature rises to 85.0°C and the tire's interior volume increases by 3.00%. What is the new tire pressure (absolute) in pascals? Pa

Volume of the balloon is 11.79 L at 40.0 degrees Celsius and a pressure of 153 torr. What volume will the balloon have at standard temperature and pressure (STP)? Gas Laws Formulas V1P1 V2P2 Boyle's Law V,P1 = V2P2 Combined Gas Law %3D T1 T2 V1 V2 T T Charles' Law Dalton's Law Ptotal = P1 + P2+ P3. MM2 MM1 P1 P2 rate, Gay-Lussac's Law Graham's Law T T rate2 V1 V2 PV = nRT L·atm %3D Avogadro's Law Ideal Gas Law R = 0.0821- n1 n2 mol K O 2.07 L 3.60 L 4.55 L 5.06 L ||

Incandescent lightbulbs are filled with an inert gas to lengthen the filament life. With the current off ( at T = 20.0 degrees Celsius ), the gas inside a lightbulb has a pressure of 113 kPa. When the bulb is burning, the temperature rises to 89.4 degrees Celsius. What is the pressure at the higher temperature?

Step 1 (a) The ideal-gas equation describes each condition of the air in the tire. We will set up ratios in order to describe these changes. Dividing the equations PV = nRT in the initial and final states, we have PfVf Tf P¡Vi Ti Solving for the final pressure in the tire, gives Pf = = = which gives I Tf P(V)() P₁ Vf T₁ = (1.013 x 105 Pa) x 105 Pa. Note that the volume V¡ cancels out of the equation. = Vf Po = Pr (V ( ) ( ) Pd Pf Vi V₁ Step 2 (b) After the car is driven, the temperature and volume of air in the tire have changed. Let Td be the temperature and Vd be the volume of air in the tire. We have PdVd Td PfVf Tf' x 105 Pa 273 + 273 + Vf Vf Again we see that the volume Vf cancels out of the equation. °C K °℃ K = x 105 Pa.

A hot air balloon holds 7.40 x 107 liters of gas. In order for the hot air balloon to rise into the sky, it must be heated to 120°C. Once the balloon is up in the air, the air needs to be cooled in order for the balloon to land. If the temperature of the balloon is decreased to 40.0°C, what will the new volume of the gas be? SOMEONE PLEASE HELP ME!!

A hot air balloon uses the principle of buoyancy to create lift. By making the air inside the balloon less dense then the surrounding air, the balloon is able to lift objects many times its own weight. A large hot air balloon has a maximum balloon volume of 2090 m3. a.  If the air temperature in the balloon is 54 °C, how much additional mass, in kilograms, can the balloon lift? Assume the molar mass of air is 28.97 g/mol, the air density is 1.20 kg/m3, and the air pressure is 1 atm.

What is the value of gas constant? a) 8.314 kJ mol-1K-1 b) 8.314 L atm mol-1K-1 c) 0.0821 L atm mol-1K-1 d) It is equal to the constant in PV/T = constant

Large helium-filled balloons are used to lift scientific equipment to high altitudes. (a)What is the pressure inside such a balloon (in atm) if it starts out at sea level with a temperature of 24.8°C and rises to an altitude where its volume is sixteen times the original volume and its temperature is  −41.7°C?  (Enter your answer to at least 3 decimal places) _______________ atm   (b)What is the gauge pressure? (Enter your answer in atm and to at least 3 decimal places. Assume atmospheric pressure is constant.) ________________ atm