Suppose that white is the dominant phenotype in sea slugs. Assuming simple dominance, what will be the result of a cross between P1 generation true-breeding lines of purple and white sea slugs? mostly purple sea slugs in the F1 generation, with an occasional white sea slug all purple sea slugs in the F1 generation, but a lighter purple than in the parents all white sea slugs in the F1 generation all purple sea slugs in the F1 generation

Suppose that white is the dominant phenotype in sea slugs. Assuming simple dominance, what will be the result of a cross between P1 generation true-breeding lines of purple and white sea slugs? mostly purple sea slugs in the F1 generation, with an occasional white sea slug all purple sea slugs in the F1 generation, but a lighter purple than in the parents all white sea slugs in the F1 generation all purple sea slugs in the F1 generation

Name: Suppose that white is the dominant phenotype in sea slugs. Assuming s
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Description: Suppose that white is the dominant phenotype in sea slugs. Assuming simpledominance, what will be the result of a cross between P1 generation true-breedinglines of purple and white sea slugs?mostly purple sea slugs in the F1 generation, with an occa

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter3: Transmission Of Genes From Generation To Generation

Section: Chapter Questions

Problem 18QP: More Crosses with Pea Plants: The Principle of Independent Assortment Determine the possible...

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More Crosses with Pea Plants: The Principle of Independent Assortment Determine the possible genotypes of the following parents by analyzing the phenotypes of their children. In this case, we will assume that brown eyes (B) is dominant to blue (b) and that right-handedness (R) is dominant to left-handedness (r). a. Parents: brown eyes, right-handed brown eyes, right-handed Offspring: 3/4 brown eyes, right-handed 1/4 blue eyes, right-handed b. Parents: brown eyes, right-handed blue eyes, right-handed Offspring: 6/16 blue eyes, right-handed 2/16 blue eyes, left-handed 6/16 brown eyes, right-handed 2/16 brown eyes, left-handed c. Parents: brown eyes, right-handed blue eyes, left-handed Offspring: 1/4 brown eyes, right-handed 1/4 brown eyes, left-handed 1/4 blue eyes, right-handed 1/4 blue eyes, left-handed
Suppose that a gene affects the anterior morphology in house flies andis inherited as a maternal effect gene. The gene exists in a functionalallele, H, and a recessive nonfunctional allele, h, which causes a smallhead. A female fly with a normal head is mated to a true-breedingmale with a small head. All of the offspring have small heads. Whatare the genotypes of the mother and offspring? Explain your answer
In fruit flies, the allele for normal wings (V) is dominant to the allele for short wings (v). Suppose two fruit flies heterozygous for the trait are mated. What is the male fruit fly’s genotype and the female fruit fly’s genotype? What is the male fruit fly’s phenotype and the female fruit fly’s phenotype? What will be the genotypic ratio of the F1 generation? What will be the phenotypic ration of the F1 generation?
Honeybees are unusual in that male bees (drones) have only onecopy of each gene, but female bees have two copies of their genes.This difference arises because drones develop from eggs that havenot been fertilized by sperm cells. In bees, the trait of long wingsis dominant over short wings, and the trait of black eyes is dominant over white eyes. If a drone with short wings and black eyeswas mated to a queen bee that is heterozygous for both genes, what are the predicted genotypes and phenotypes of male and femaleoffspring? What are the phenotypic ratios if we assume an equalnumber of male and female offspring?
A pea plant is heterozygous for three genes (Tt Rr Yy), whereT = tall, t = dwarf, R = round seeds, r = wrinkled seeds, Y = yellowseeds, and y = green seeds. Tall, round, and yellow are the dominanttraits. What is the probability that an offspring from self-fertilizationof this plant will be tall with wrinkled, yellow seeds?
You set up a cross between a male fruit fly with lobe eyes and a true breeding female fruit fly with reduced bristles and disrupted wings. In the F1 offspring you see the all the flies have WT bristles and WT wings. However, half the flies have WT eyes and half the flies have lobe eyes. You take 20 of the F1 female flies with lobe eyes and mate them to 20 true breeding male flies with reduced bristles and disrupted wings and observe the following offspring: 169 lobe eyes and reduced bristles 137 lobe eyes and disrupted wings 637 reduced bristles and disrupted wings 158 reduced bristles 36 wildtype 174 disrupted wings 657 lobe eyes 32 lobe eyes reduced bristles and disrupted wings Fruit flies are unusual in that the male fruit flies do not undergo crossovers during meiosis. If you had taken 20 of the F1 Males with lobe eyes and crossed them to 20 females that were true breeding for reduced bristles and disrupted wings what phenotypes and in what proportions would you expect in the…
Most of the feathers of erminette fowl are light colored, with an occasional black one, giving a fleckedappearance. A cross of two erminettes produced a totalof 48 progeny, consisting of 22 erminettes, 14 blacks,and 12 pure whites. What genetic basis of the erminette pattern is suggested? How would you test yourhypotheses?
(This one is more complicated). Two true breeding fruit flies are allowed to mate. One fly ishomozygous dominant for body color and eye color while the other is homozygous recessive forbody color and eye color. (g+:gray body, g:black body, e+:ebony eyes, e:red), The F1 flies areallowed to mate. What are the following probabilities in the F2 generation? For this problemmake sure to show the Punnett Square for your F2 generation and all of your calculations. Youdo not need to show the Punnett Square for the F1 generation. Answer in percent and round to 2decimals.a. Two of three fruit flies are gray and red.b. The first fruit fly is gray and ebony, the second fruit fly is gray and red, and the third fruit fly is black and ebony.
Flower color in snapdragons is an incompletely dominant trait; progeny of crosses between true- breeding red- and white-flowered plants have pink flowers. A cross between two snapdragon plants yielded progeny with all 3 flower colors. What can be inferred about the phenotypes of the parents? O We cannot infer the phenotypes of the parents Both parents had red flowers O One parent had red flowers and the other had white flowers O Both parents had pink flowers O Both parents had white flowers
Snapdragons occur in nature as either green- or yellow-leaved plants. Suppose that a gardener crosses two yellow-leaved snapdragons, and one-third of the offspring have green leaves while two-thirds of the offspring have yellow leaves. What is the most likely explanation for this outcome? The allele causing yellow leaves is a recessive epistatic allele O The allele causing yellow leaves is carried in the chloroplast genome O The allele causing yellow leaves is a dominant lethal allele The allele causing yellow leaves is a recessive lethal allele
Doesn't the The F1 offspring being all LlDd means that the F1 centipedes have long legs and DARK colored bodies. Since D (dark) is dominant to to d (light)? Then if you drew a punnett swuare, wouldn't all the offspring being LlDd mean that none of the offspring have light bodies and short legs? So I don't understand the 25/4 fraction that you got for part a and where did the 1/16 come from?
In jellyfish, let's say that long tentacles are produced by a sex-influenced allele that is dominant in males and recessive in females. Let B1 = long and B2 = short. Which of the following correctly diagrams a cross between a female with long tentacles and a male with short tentacles? O B1B1XX X B1B2XY O B1B2 XX X B1B2 XY O females with long tentacles do not exist, so this cross is impossible O B1B1 XX X B2B2 XY O X(B1) X(B2) x X(B2) Y