Database System Concepts
7th Edition
ISBN: 9780078022159
Author: Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher: McGraw-Hill Education
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- Given what we know about transmission delay and the following: A web client and a web server separated by one intermediary router. • Each link carries data at 1Mbps with an MTU of 8192 bytes • Each link is 1000 km long with a propagation speed of 250000 km/s • Zero processing and queueing delays • Connection management packets (packets used for opening a connection, confirming a connection and acknowledging receipt of information) contain no data and all packets have 125 bytes of overhead on top of any data they may contain. • The web client makes an HTTP request to the server that is 250 bytes long. • The requested data is 4 kilobytes in size with 500 bytes of overhead for the HTTP status and headers What is the RTT to open the connection? а. b. How long would it take for a web client to complete the request? You can ignore any time needed to close the connection.arrow_forwardAn Internet user would like to transfer a message from his computer (host A) to another computer (host B). The size of the message passed to the IP layer is 3800 bytes. The datagram(s) carrying the message will have to cross two routers (R1 and R2) and 3 networks (NET1, NET2, and NET3) as described in the above figure. Each of these networks has a specific MTU (for example the MTU of network 1 is 1500 bytes. MTU here stands for Maximum Transmission Unit, the largest data that a frame can carry). Fill the table with the IP datagram(s) needed right after passing through NET3 (no need to show your fragmentation for N1 or N2). Assume a 2-byte options in the header. Show all your details (for partial points in case your numbers are incorrect). NET1 MTU=1500 R1 NET2 MTU=640 R2 NET3 MTU 1500 V BIU Fragment # Format Offset Flag (3 bits) Data Length Total Length ...arrow_forwardI need helparrow_forward
- 2. Consider a slotted TDM hierarchical network in which there are 8 computers sharing a 10 Mbps channel to a router R1, sending packets to R1 which must all be forwarded by R1 over an outgoing link (called the MAN link), as shown in Figure 1. Computers A-H always have packets waiting to be sent, so no timeslot on the shared LAN is idle. Ignore the propagation delay on the LAN. The MAN link outgoing from R1 is a 100 Mbps link. The network layer protocol in use has a PDU with exactly 40 bytes of header and exactly 200 bytes of payload (SDU). The DLC layer protocol in use on the LAN has a PDU with exactly 40 bytes of header and 20 bytes of trailer. The DLC layer protocol in use on the outgoing link from R1 has a PDU with 40 bytes of header and no trailer. The physical layer does not impose any bit overhead in either channel. Use 1 Mbps = 1000000 bps. B D E F G H R1 R2 Figure 1 (a) What is the transmission delay of a bit for Computer A? (b) What is the transmission delay of a DLC PDU for…arrow_forwardConsider a typical (dumb layer 2) switch. It receives a packet on one of its ports. How does it know what to do with this packet? Are there any situations where such a switch would be unable to handle a packet? If so, describe them. If not, explain why it is impossible.arrow_forward
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