Suppose a geneticist uses a three-point testcross to map three recessive, linked hummingbird wing-shape mutations called tn, f and b, where tn is associated with thin wings, fis associated with flat wings, and b is associated with blunt wings. He first crosses homozygous blunt birds to homozygous thin, flat birds. Next, he testcrosses the F₁ progeny to thin, flat, blunt birds. He obtained the results shown. Given this data, label the progeny phenotypic classes as either parental, single crossover (SCO), or double crossover (DCO) recombinant types. Each label may be used multiple times. Two classes have already been filled in. Phenotype blunt thin, flat flat thin, blunt thin flat, blunt thin, flat, blunt wild type Number 821 785 171 191 7 7 28 24 Recombinant type SCO SCO Answer Bank parental SCO DCO

Suppose a geneticist uses a three-point testcross to map three recessive, linked hummingbird wing-shape mutations called tn, f and b, where tn is associated with thin wings, fis associated with flat wings, and b is associated with blunt wings. He first crosses homozygous blunt birds to homozygous thin, flat birds. Next, he testcrosses the F₁ progeny to thin, flat, blunt birds. He obtained the results shown. Given this data, label the progeny phenotypic classes as either parental, single crossover (SCO), or double crossover (DCO) recombinant types. Each label may be used multiple times. Two classes have already been filled in. Phenotype blunt thin, flat flat thin, blunt thin flat, blunt thin, flat, blunt wild type Number 821 785 171 191 7 7 28 24 Recombinant type SCO SCO Answer Bank parental SCO DCO

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Description: Suppose a geneticist uses a three-point testcross to map three recessive, linked hummingbird wing-shape mutations called tn, f,and b, where tn is associated with thin wings, f is associated with flat wings, and b is associated with blunt wings. He f

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter15: Genomes And Genomics

Section: Chapter Questions

Problem 2QP: Hemophilia and color blindness are both recessive conditions caused by genes on the X chromosome. To...

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A geneticist is using a three-point testcross to map three linked Drosophila recessive mutations called a, b, and c, where a is associated with anomalous gait, b is associated with buckled wings, and c is associated with curved bristles. She first crosses homozygous anomalous, buckled flies to homozygous curved flies. Next, she testcrosses the F₁ progeny to anomalous, buckled, curved flies. She obtains 1000 progeny distributed as shown. From this data, calculate the map distance between b and c. Testcross progeny phenotype curved anomalous, buckled wild type anamalous, buckled, curved buckled, curved anomalous anomalous, curved buckled Number 277 283 4 6 133 127 83 87 map distance: m. u.
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