Soultion H.w X (W) = x(+) ēd± -JWE X₁ y₁ X(+) X, Y, X2 Y2 (-1,0) (0,2) m= (0,1) (0,2) 42-41-2-1 m. Yey 2-0 me your 201 X2-X1 X2-X1 2 m= = => 2 m=2 Y-Y₁ = m (X-X₁) 4-0=2(x-(-1)) Y=2(x+1) =2++2 Y-Y₁=m(x-x1) 1-1=2(x-0) Y-1=2X y=2++1 -JWE X (W) = 5° X(+) == W² d+ + 9° X(+) How to result X(w)=2/ sin뿔 X (W) = 2 (sin ĕjwt dt 2

From step1, how did you get that 50+(80*j60/80+j60) = 78.8+j38.4? also in step 2, how did you get that 5/(0.0125-0.0167) = 143.63 + j191.89?

Can someone please explain how Rc1 and Xm1 are found from this?

Identify which measurement this oscilloscope time difference reading is useful for. Oscilloscope-XSC1 Channel_B Channel_A 169.064 V 113.590 V -55.474 V Time T1 Reverse 250.000 us 89.282 V 122.375 V 33.093 V T2 382.576 us T2-T1 132.576 us Save Ext. trigger Timebase Scale: 200 us/Div X pos. (Div): 0 Channel A Scale: 100 V/Div Y pos. (Div): 0 Channel B Trigger Scale: 100 V/Div Y pos. (Div): 0 Edge: f 2 AB Ext Level: Y/T Add B/A A/B AC0 DC AC0 DC Single Normal Auto None O none of the above O phase shift O period

I need the answer as soon as possible

Hello. I keep getting weird answers and I don't think I am going about this correctly. Could you help me out with this problem? Thank you for your tim

THE SWITCH HAs BEtw IN PositINN "a" FOR A LoNG TrmE. tooKe a) At TemE t= o, THE SWITCH /s Mouro To Pasirned "b". DETERMINE Time ti WHICH Is THEe TimE To REoucE THE CAPACITOR VOLTAGE To Oue-HALe Its wiTIAL VOLTACE. b) FuD THE CURRENT Ar Time ti ¿(ti),

Why this happening to my circuit? I am inputting a 0-3.3 V sine wave into my voltage follower circuit using NE5532P. At the output I am seeing 0-3.3 V sine wave as expected. However, when I add a 1000 uF capacitor and a loudspeaker to listen to the sine wave my wave is clipped and its reading -800 mV for min and +680 mV for max on the oscilloscope. How do I fix this so that I only listen to 0-3.3 V sine wave? I'm in the lab and this is confusing to me.

Hello. I would appreciate some help with this problem. Thank you

can you help me