Solve for the currents in various branches of the circuit shown in the figure below: V1= 25 V; V2= 10V 62 V1 V2 42 82
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- You are working as an electrician in a large steel manufacturing plant, and you are in the process of doing preventive maintenance on a large DC generator. You have megged both the series and shunt field windings and found that each has over 10 M to ground. Your ohmmeter, however, indicates a resistance of 1.5 across terminals S1andS2. The ohmmeter indicates a resistance of 225 between terminals F1andF2. Are these readings normal for this type machine, or is there a likely problem? Explain your answer.a) Find the currents I1, I2, and I3 flowing on the circuit in the figure. b) What current flows in the opposite direction to the assumed direction? c) Using kirchoff's rules, calculate the potential differences between points c and e by following the following ways. path 1 = c-d-e path 2 = c-d-a-e path 3 = c-b-a-eThe circuit below(left) displays a schematic diagram of a battery. The voltage measured by U1 is called the terminal voltage given R1 = 1 ohm. In the circuit below(right), the terminal voltage of each of the battery-resistor combination is VT = 1.5 volts. Find the voltage across R1 & voltage of the battery.
- 4.-For-labeled currents, draw an arrow to show the direction of the actual positive current. For labeled voltages, circle the node that is at the actual highest potential. Note that the positive and negative signs of the voltage represent the polarity of the probes of a voltmeter connected to the device. The value shown is the reading on the voltmeter. (segment of wire) 2A -2A -5A 2.de 3A TA Cov E 5V 12V + 3V -10V -2013. The figure on the left below shows a schematic diagram of a battery. The voltage measured by U1 is called the terminal voltage given R1 = 1 ohm. In the figure on the right below, the terminal voltage of each of the battery-resistor combination is Vr = 1.5 volts. Find the following: a. The current passing through R5. b. The currents passing through R1 and R3 C. The voltage across R1. d. The voltage of the battery EMF. e. The percentage of voltage loss ot the battery due to the internal resistance R1. The power dissipated by the internal resistance R1. g. The power dissipated by R5 if R1 = R2 = R3 = R4 = 0. h. The percentage of power dissipation loss due to the four resistors R1, R2, R3, and R4 f. R1 R3 S10 R1 U1 1.500 EMF EMF R5 100 V1 R2 $10 EMF R4 EMF EMFA current of 5 amperes enters a parallel combination of two unequal, unknown resistors (R1 and R2) supplied from a 45 volts DC source. If the two resistors are connected in series, the current drawn from the same source decreases to 937.5 mA. R1 has a lesser resistance than R2. Find R1 and R2. (show complete solution)
- Ques 4. An electric circuit consists of four resistors, R1 = 12 Ohm, R2 = 12 Ohm, R3 = 3 Ohm and R4 = 6 Ohm, and are connected with a source of emf E1 = 6 Volt, E2 = 12 Volt. Determine the electric current flows in the circuit as shown in the figure below. I E₂ R₂(a) Identify the type of circuit in Figure 4. Determine its functionalities and find the appropriate mathematical equation. Sig_1 Sig_2 Sig_3+ Sig_4 Iin. Iin. Iin Iin GND www.5 R5 www R4 www R3 ww R2 ww R1 Feedback Resistor ลบ Figure 4 Iout VOUT ◆ BUExplain and show full solution
- R3 R4 R5 Consider the circuit, as shown in the figure above. R₁ - 10.0 ohm, R₂ = 11.0 ohm, Ry 5.00 ohm, R4 = 5.00 ohm, Rs 22.0 ohm and V = 25.0 V. Calculate the magnitude of the current in the Rs = 22.0 ohm resiston Submit Answer Incorrect. Tries 2/6 Previous Tries Calculate the magnitude of the potential difference between points a and b. Submit Answer Incorrect. Tries 1/6 Previous TriesA PMMC instrument has a three-resistor Ayrton shunt connected across it to make an ammeter as in Figure 2. The resistance values are R1 = 4.52, R2=0.452 and R3= 0.052. The meter has Rm = 1k2 and Ifs.d = 50µA. Calculate the three ranges of the ammeter. [10.05mA, 100.05mA, 1.005A] Rm=1k2 B R3 R R, Selector Figure 2 수Find the potential difference between point a and point b for the situation shown below. Here ₁ = 12.0 V, E₂ = 7.77 V and R₁ = 4.33 №, R₂ = 6.44 , and R3 = 2.28 2. Va - Vb = R₂ E2 b R3 www R₁ &₁